Yes. Think of it as a fraction -
12/6 reduces to 4/2.
4/2 > 3/2.
6 treats in each bag.
First, since there were 3 batches of 24 treats, multiply 3 by 24 to get the total amount of treats
3•24=72 treats in total
Next, divide 72 by 12 to get how many treats will go in each bag.
72/12= 6 treats in each bag.
Next,
<span>Let the total hour of exam is 3hrs ie 180 minutes.( since answer required in minutes).
Let as assume maths questions be in x minutes.
Let the assume rest of the question is in y minutes.
Given that out of 320 qns 40 is maths qns.
therefore, maths qn is =40 and rest of qns is 280.
Also given the time of maths qns is twice of rest. They related in the following equation. ie x:y=2:1 ; x/y =2/1
ie x=2y
therefore 2x+y= 180 min ; ie 2(2y)+y= 180 ; y=36
therefore resolving for x = 2*36 = 72
time spent for maths qn is 2*x = 2* 72 =144min.
rest of maths question is 36 min.</span>
Hello :
<span>F(x) = x² + 3x - 2
</span><span>F(-1) = (-1)²+3(-1) -2
</span>F(-1) = 1 - 3 -2 =1 - 5
F(-1) = -4
