The solution to the expressions given are;
9 -9t/ 12 - 5t
a. 20/ 169
b. -170/ 169
c. 386/ 169
d. -10/ 169
<h3>How to solve the expressions</h3>
Given:
We can see that both variables in the numerator and denominator have no common factor, thus cannot be factorized further
a. 
First, let's find the lowest common multiple
LCM = 169
= 
= 
= 20/ 169
b. 
The lowest common multiple is 119
= 
substract the numerator
= - 170/ 119
c.
The lowest common multiple is 169
= 
= 386/ 169
d. 
The lowest common multiple is 169
= 
= - 10/ 169
Thus, we have the solutions to be 9 -9t/ 12 - 5t, 20/ 169, -170/ 169, 386/ 169, -10/ 169 respectively.
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The denominator of a fraction cannot be zero.Therefore in h(x) = f(x)/g(x), g(x) cannot equal zero, x + 6 cannot equal zero, x cannot equal -6. The domain of h(x) is ℜ - {-6}.
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36 donuts (2 1/2 dozen) = $8.00
So, you divide 8 by 36 and you get about 22¢ for each donut. Then, you do .22 x 12 which equals $2.64.
One dozen donuts = $2.64
Answer:
x = 5 and -2
Step-by-step explanation:
Given the function of x to be;
f(x) = (x-5)(x+2)/x+1
The value of x that will make the function zero can be calculated for by equating the given function to zero first to have;
If f(x) = 0, then;
(x-5)(x+2)/x+1 = 0
Cross multiplying;
(x-5)(x+2) = 0
(x-5) = 0 and x+2 = 0
x = 5 and x = -2
The value of x that will make the function zero is therefore 5 and -2
6.241 I think that's right
