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Nataly_w [17]
3 years ago
13

What is the first step in the construction of a line perpendicular to and passing through an external point M? Assume that the c

onstruction uses only a compass and a straightedge.
A.
Place the compass needle on M and, keeping the compass width the same, draw two arcs that intersect .

B.
Place the compass needle at any point on , and set the compass width to M.

C.
Draw a line from point M passing through , and mark the point of intersection.

D.
Place the compass needle at any two points on , and draw two arcs through M.
Mathematics
1 answer:
AVprozaik [17]3 years ago
4 0

Answer:

A.)lPace the compass needle on M and, keeping the compass width the same, draw two arcs that intersect

Step-by-step explanation:

In the construction of a line perpendicular to AB←→ and passing through an external point M the first step must be"Place the compass needle on M and, keeping the compass width the same, draw two arcs that intersect AB←→". After that you can draw arcs from intersection points (keeping the compass width same as before) to the opposite side of M, name it as N than use straightedge to draw line passes through M and n that would be perpendicular line to AB.

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Solve (x+2<5) u (x-7>-6)
FrozenT [24]

Answer:

{x | x<3 or x>1}

Step-by-step explanation:

x+2<5

x<5-2

x< 3

x-7> -6

x> -6+7

x>1

symbol U means union

5 0
2 years ago
Consider the square root function f(x) = sqrt x + 2 + 1 to complete the table of values below. find each missing value and then
Scrat [10]

Given the function :

f(x)=\sqrt[]{x+2}+1

We need to find each missing value

Given x = -3 , -2 , -1 , 2 , 7

So, substitute with each value of x to find the corresponding value of f(x)

x=-3\rightarrow f(x)=\sqrt[]{-3+2}+1=\sqrt[]{-1}+1

So, there is no value for f(x) at x = -3 (the function undefined because the square root of -1)

\begin{gathered} x=-2\rightarrow f(x)=\sqrt[]{-2+2}+1=\sqrt[]{0}+1=0+1=1 \\  \\ x=-1\rightarrow f(x)=\sqrt[]{-1+2}+1=\sqrt[]{1}+1=1+1=2 \\  \\ x=2\rightarrow f(x)=\sqrt[]{2+2}+1=\sqrt[]{4}+1=2+1=3 \\  \\ x=7\rightarrow f(x)=\sqrt[]{7+2}+1=\sqrt[]{9}+1=3+1=4 \end{gathered}

the graph of the function and the points will be as shown in the following image :

5 0
1 year ago
PLEASE help with these math questions
kaheart [24]
1. C
2. A
3. D
4. 62/25
5. 4/33

By the way it is not fair. posting 5 sums for just 7 points. :)

anyway, if it helped u
do click thx.

3 0
3 years ago
LET me know how you got the answer
andre [41]

6/2*3 / 3(3)

First simplify the numerator: 6/2*3 = 3*3 = 9

Next simplify the denominator: 3(3) = 3*3 = 9

So you have 9/9, which equals 1.


The 3rd answer is correct.

6 0
3 years ago
Read 2 more answers
The product of two consecutive numbers is 182
kupik [55]
2 consecutive numbers....x and x + 1

x(x + 1) = 182
x^2 + x = 182
x^2 + x - 182 = 0
(x - 13)(x + 14) = 0

x - 13 = 0
x = 13

x + 14 = 0
x = -14....not this one because it is negative

x + 1 = 13 + 1 = 14

ur 2 numbers are : 13 and 14
8 0
3 years ago
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