<span>A chord divides a circle into 2 segments.
A major segment and a minor segment.
If the chord passes through the center of the circle, then it divides the circle into equal segments.</span>
Answer:
The area should be 170
Step-by-step explanation:
L× W =70×10=170
Answer:
f(2) = 2.5×2-10.5
=5-10.5
=-5.5
g(2) = 64(0.5×2)
= 64×1
=64
f(3)=2.5×3-10.5
=7.5-10.5
=-3
g(3)=64(0.5×3)
=64×1.5
=96
f(4)=2.5×4-10.5
=10-10.5
=-500
g(4)=64(0.5×4)
=64×2
=128
f(5)=2.5×5-10.5
=12.5-10.5
=2
g(5)=64(0.5×5)
=64×2.5
=150
I think it is the processs It will help you
Answer:
The calculated χ² = 0.57 does not fall in the critical region χ² ≥ 12.59 so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.
Step-by-step explanation:
1) We set up our null and alternative hypothesis as
H0: proportion of fatal bicycle accidents in 2015 was the same for all days of the week
against the claim
Ha: proportion of fatal bicycle accidents in 2015 was not the same for all days of the week
2) the significance level alpha is set at 0.05
3) the test statistic under H0 is
χ²= ∑ (ni - npi)²/ npi
which has an approximate chi square distribution with ( n-1)=7-1= 6 d.f
4) The critical region is χ² ≥ χ² (0.05)6 = 12.59
5) Calculations:
χ²= ∑ (16- 14.28)²/14.28 + (12- 14.28)²/14.28 + (12- 14.28)²/14.28 + (13- 14.28)²/14.28 + (14- 14.28)²/14.28 + (15- 14.28)²/14.28 + (18- 14.28)²/14.28
χ²= 1/14.28 [ 2.938+ 5.1984 +5.1984+1.6384+0.0784 +1.6384+13.84]
χ²= 1/14.28[8.1364]
χ²= 0.569= 0.57
6) Conclusion:
The calculated χ² = 0.57 does not fall in the critical region χ² ≥ 12.59 so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.
b.<u> It is r</u>easonable to conclude that the proportion of fatal bicycle accidents in 2015 was the same for all days of the week
His answer is not reasonable because 5/8>4/3
