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tekilochka [14]
2 years ago
13

Will give brainliest give the answer and steps

Mathematics
1 answer:
tester [92]2 years ago
3 0

Answer:B=8

Step-by-step explanation:

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f(1)= (1)^2+ 2(1) -1

= 2

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What is the measurement of x in the equation. 8x+5x+2x-11+6=180
34kurt

Answer:

x = 37/3 = 12.333

Step-by-step explanation:

Step  1  :

Pulling out like terms :

1.1     Pull out like factors :

  15x - 185  =   5 • (3x - 37)

Equation at the end of step  1  :

Step  2  :

Equations which are never true :

2.1      Solve :    5   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2      Solve  :    3x-37 = 0

Add  37  to both sides of the equation :

                     3x = 37

Divide both sides of the equation by 3:

                    x = 37/3 = 12.333

4 0
3 years ago
“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor
Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

C=2\pi r

<u><em>Find the radius of the sphere with a 5.50-meter circumference</em></u>

For C=5.50\ m

assume

\pi =3.14

substitute and solve for r

5.50=2(3.14)r

r=5.50/[2(3.14)]=0.88\ m

<u><em>Find the radius of the sphere with a 7.85-meter circumference</em></u>

For C=7.85\ m

assume

\pi =3.14

substitute and solve for r

7.85=2(3.14)r

r=7.85/[2(3.14)]=1.25\ m

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

SA=4\pi r^{2}

<u><em>Find the surface area of sphere with a 5.50-meter circumference</em></u>

For r=0.88\ m

assume

\pi =3.14

substitute

SA=4(3.14)(0.88)^{2}

SA=9.73\ m^{2}

<u><em>Find the surface area of sphere with a 7.85-meter circumference</em></u>

For r=1.25\ m

assume

\pi =3.14

substitute

SA=4(3.14)(1.25)^{2}

SA=19.63\ m^{2}

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

<u><em>Find the cost of sphere with a 5.50-meter circumference</em></u>

9.73*(92)=\$895.16

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

<u><em>Find the cost of sphere with a 7.85-meter circumference</em></u>

19.63*(92)=\$1,805.96

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

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Answer:

44.5 is the best

Step-by-step explanation:

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yan [13]

Answer:

$57.93

Step-by-step explanation:

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