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lisabon 2012 [21]
2 years ago
9

Graph the function with the given domain. Then identify the range of the function. y = -6; domain: x ≥ 5

Mathematics
2 answers:
hjlf2 years ago
8 0

Answer: Plot a point at (-6,5) then just go start up. That is your graph

Step-by-step explanation:

Range is left to right so that means that the only point on the x axsis you can plot is -6 and the domain is up and down so you cant plot a point below 5

mojhsa [17]2 years ago
4 0

Answer:

Plot a point at (-6,5) then just go start up

Step-by-step explanation:

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Find the slope of the line in simplest form.
N76 [4]

Answer:

-\frac{3}{2}

Step-by-step explanation:

To find the slope of the given line, slope is the rise divided by the run of a line.

  Slope  = \frac{y_{2} - y_{1}  }{x_{2} - x_{1}  }

  Picking points (4, 18)  and (8, 12)

 Now;

  x₁  = 4

  y₁  = 18

  x₂ = 8

  y₂ = 12

  Slope  = \frac{12 - 18}{8-4}   = -\frac{6}{4}   = -\frac{3}{2}

7 0
3 years ago
In triangle ABC shown below, DE is parallel to AC. The following two-column proof with missing statements and reasons proves tha
lianna [129]

Answer:

The correct option is;

C. 3. ∠BDE ≅∠BAC, Corresponding Angles Postulate 4. ∠B ≅ ∠B Reflexive Property of Equality

Step-by-step explanation:

The two column proof can be written as follows;

Statement,                         Reason

1. \overline{DE} \parallel \overline{AC},                           Given

2. \overline {AB} is a transversal ,         Conclusion from statement 1.

We note that ∠BDE  and ∠BAC are on the same side of the transversal relative to the parallel lines, and are therefore, corresponding angles.

Therefore, we have;

3. ∠BDE ≅∠BAC,                 Corresponding Angles Postulate

Also

4. ∠B ≅ ∠B,                           Reflexive Property of Equality

In the two triangles, ΔABC and ΔDBE, we have ∠BDE ≅∠BAC and ∠B ≅ ∠B,

From ∠BDE + ∠B + ∠BED = 180°

∠BAC + ∠B +  ∠BCA = 180°

Therefore, ∠BED = ∠BCA Substitution property of equality

Which gives;

5, ΔABC ~ ΔDBE,          Angle Angle Similarity Postulate

6. BD/BA = BE/BC,      Converse of the Side-Side-Side Similarity Theorem

5 0
3 years ago
Angle JKL is a straight angle. The measure of angle MKL is 85°. The measure of angle JKM is xº. What is the value of x?​
iris [78.8K]

Answer:

  • 95°

Step-by-step explanation:

<u>Straight angle is 180°</u>

  • JKL = MKL + JKM
  • 180° = 85° + x
  • x = 180° - 85°
  • x = 95°
8 0
3 years ago
Help me pleaseeeeeeeeeeeeeeeeee
dem82 [27]
Hello:
Increase in length is : (30×10)/100 =3 cm
Increase in width is : (20×5)/100 = 1 cm
the new length is : 30 cm+3cm =33 cm
the new width is : 20cm+1 cm =21 cm
the perimeter is : 2(20+30) = 100 cm
the new perimeter is : 2(33+21) = 108 cm 
the pourcentage increase in the perimetr is : 8%
108 =100/100+8/100=1+8/100




8 0
3 years ago
Think of a trapezoid with b1 and b2 as the length of the bases, h as the length of the altitude, and A as the area. Find the mis
Marina86 [1]
Area = 1/2 x (sum of bases) x height
18 = 1/2 x (6 + b2) x 2
b2 = 12.
3 0
3 years ago
Read 2 more answers
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