65 sequences.
Lets solve the problem,
The last term is 0.
To form the first 18 terms, we must combine the following two sequences:
0-1 and 0-1-1
Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent
So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:
2x + 3y = 18
Case 1: x=9 and y=0
Number of ways to arrange 9 identical 2-term sequences = 1
Case 2: x=6 and y=2
Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28
Case 3: x=3 and y=4
Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35
Case 4: x=0 and y=6
Number of ways to arrange 6 identical 3-term sequences = 1
Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65
Hence the number of sequences are 65.
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Answer: 40x+18
Step-by-step explanation:
Answer:
Out of every 5 rectangles 2 shall be purple.
3 scarves have 3 times 5 rectangles.
Thus they shall be 3 times 2 that are purple.
Step-by-step explanation:
Answer: Choice D) 5
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Notice the hole at (1,2). This means x = 1 and y = 2
y = f(x)
y = f(1) after we replace x with 1
y = 2
If we go from f(x) to f(x-4), then we shift the xy axis four units to the left. The curve will stay still though it will move relative to the xy axis. The xy axis moves four units to the left, so it appears that the curve moved 4 units to the right.
Add 4 to the x coordinate:
x = 1 ---> x+4 = 1+4 = 5
The y coordinate stays the same. No vertical shifting is done.
So we go from (1,2) to (5,2)
(1,2) is a hole on y = f(x)
(5,2) is a hole on y = f(x-4)
This is why the answer is x = 5
Answer:
B
Step-by-step explanation:
