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postnew [5]
2 years ago
10

When a business buys a fast food franchise, it is buying the recipes used at every restaurant with the same name. For example, a

ll Pizzeria Specialty House Restaurants have different owners, but they must all use the same recipes for their pizza, sauce, bread, etc. You are now working at your local Pizzeria Specialty House Restaurant, and listed below are the amounts of meat used on one meat-lovers pizza.
1/4 cup of sausage 1/3 cup of pepperoni
1/6 cup of bacon 1/ 8 cup of ham
1/ 8 cup of beef
What is the total amount of toppings used on a meat-lovers pizza? _________________________ cup(s)
Mathematics
1 answer:
den301095 [7]2 years ago
8 0

Answer:

1 cup

Step-by-step explanation:

1/4= 6/24

1/3= 8/24                    --------

1/6= 4/24                    --------             24/24 = 1

1/8= 3/24                    

1/8= 3/24

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What is the product of the 2 solutions of the equation x^2+3x-21=0
Advocard [28]
X²+3x-21=0

1) we solve this square equation:
x=[-3⁺₋√(9+84)] / 2=(-3⁺₋√93)/2
We have two solutions:
x₁=(-3-√93)/2
x₂=(-3+√93)/2

2) we compute the product of the 2 solutions found.
[(-3-√93)/2][(-3+√93)/2] =(-3-√93)(-3+√93) / 4=
=(9-93)/4=-84/4=-21

Answer: the product of the 2 solutions of this equation is -21
3 0
3 years ago
10 pink cards, 10 blue cards, and 10 yellow cards, each color-set labeled 1-10, are placed in a bucket. What is the probability
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Answer:

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8 0
3 years ago
Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v
k0ka [10]

I'll use subscript notation for brevity, i.e. \frac{\partial f}{\partial x}=f_x.

By the chain rule,

z_u=z_xx_u+z_yy_u

z_v=z_xx_v+z_yy_v

z_w=z_xx_w+z_yy_w

We have

z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}

and

\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}

When u=1,v=1,w=0, we have

\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}

and the partial derivatives take on values of

\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}

So we end up with

\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}

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The blank box should be equal to 4
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PilotLPTM [1.2K]

Answer:

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Step-by-step explanation:

hmu if you need more help

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3 years ago
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