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4 years ago

The number 360 is increased by 25%. The result is then decreased by 50%. What is the final number?

1 answer:

3 0

So if 360 is increased by 25%, you would end up with 450 (360 x 1.25), than if the result, 450 is decreased by 50% ( 450 x .50 = 225) (450 - 225 = 225) you would end up with 225.

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Choose the equation that satisfies the data in the table.

pychu [463]

The linear equation that satisfy the data in the table is: A. y = −4x − 4.

<h3>How to Find the Linear Equation for a Data in a Table?</h3>

Given the table attached below, find the slope (m) = change in y / change in x using two pairs of values, say, (-1, 0) and (0, -4):

Slope (m) = (-4 - 0)/(0 - (-1)) = -4/1 = -4

Find the y-intercept (b), which is the value of y when x = 0. From the table, when x = 0, y = -4.

b = -4.

Substitute m = -4 and b = -4 into y = mx + b

y = -4x + (-4)

y = -4x - 4

The equation that satisfy the data is: A. y = −4x − 4.

Learn more about the linear equation on:

brainly.com/question/4074386

#SPJ1

7 0

2 years ago

What is the x-intercept of y=6x-7

Gnoma [55]

Hello!

The x-intercept of y = 6x - 7 is 1.167.

Hope this helps! ☺♥

8 0

3 years ago

Read 2 more answers

P(k)=a^k=2 3 4 find value of a that makes this is a valid probability distribution

Vesna [10]

Sounds like you're asked to find $a$ such that

$\displaystyle\sum_{k=2}^4\mathbb P(k)=\mathbb P(2)+\mathbb P(3)+\mathbb P(4)=1$

In other words, find $a$ that satisfies

$a^2+a^3+a^4=1$

We can factorize this as

$a^4+a^3+a^2-1=a^3(a+1)+(a-1)(a+1)=(a+1)(a^3+a-1)=0$

In order that $\mathbb P(k)$ describes a probability distribution, require that $\mathbb P(k)\ge0$ for all $k$ , which means we can ignore the possibility of $a=-1$ .

Let $a=y+\dfrac xy$ .

$a^3+a-1=\left(y+\dfrac xy\right)^3+\left(y+\dfrac xy\right)-1=0$
$\left(y^3+3xy+\dfrac{3x^2}y+\dfrac{x^3}{y^3}\right)+\left(y+\dfrac xy\right)-1=0$

Multiply both sides by $y^3$ .

$y^6+3xy^4+3x^2y^2+x^3+y^4+xy^2-y^3=0$

We want to find $x\neq0$ that removes the quartic and quadratic terms from the equation, i.e.

$\begin{cases}3x+1=0\\3x^2+x=0\end{cases}\implies x=-\dfrac13$

so the cubic above transforms to

$y^6-y^3-\dfrac1{27}=0$

Substitute $y^3=z$ and we get

$z^2-z-\dfrac1{27}=0\implies z=\dfrac{9+\sqrt{93}}{18}$
$\implies y=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}$
$\implies a=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}-\dfrac13\sqrt[3]{\dfrac{18}{9+\sqrt{93}}}$

6 0

4 years ago

<< <<br> Attempt 2 of 3<br> 1 2 3<br> Simplify p(p-q) - g(q-p).<br> 4

Veseljchak [2.6K]

Answer:

$p {}^{2} - q { }^{2}$

Step-by-step explanation:

I hope this helps

4 0

2 years ago

For income tax purposes, a man uses a method called straight-line depreciation to show the loss in value of a copy machine he

PtichkaEL [24]

Answer: $500

Step-by-step explanation:

The vertical axis of the graph represents the value of the copy machine and the horizontal axis represents the years.

Using the line, one can see that in the first year, the value of the machine went from $7,000 to $6,500.

The loss in value is therefore;

= 7,000 - 6,500

= $500

<em>The needed graph is attached. </em>

6 0

3 years ago