Answer:
108 student tickets, and 176 adult tickets were sold
Step-by-step explanation:
Adult ticket $8 Call the number of adult tickets sold "a"
Student ticket $5 Call the number of student tickets sold "s"
Since we are talking about TWO consecutive days of sold out seats, the total number of seats sold were 2* 142 = 284
Then we create two different equations with the information given:
a + s = 284
8 * a + 5 * s = 1948
we can solve for s in the first equation as follows: s = 284 - a
and use it in the second equation
8 a + 5 (284 - a) = 1948
8 a + 1420 - 5 a = 1948
combining
3 a = 528
a = 528/3
a = 176
we find the number of student tickets using this answer in the substitution equation we used:
s - 284 - 176 = 108
Therefore 108 student tickets, and 176 adult tickets were sold.
Step-by-step explanation:
logx√2=1/6
<=> logx(2^1/2)=1/6
<=>1/2.logx(2)=1/6
<=>logx(2)=1/3
<=>2=x^1/3
<=>x=
Sorry I forgot the formula in the last step
X = 4, You subtract the 5x to the other side then divide the 32 by 8 to get 4.
If you would like to know what is f(2), you can
calculate this using the following steps:<span>
f(0) = 2
f(n+1) = - 2 * f(n) + 3
f(1) = - 2 * f(0) + 3 = - 2 * 2 + 3 = - 4 + 3 =
- 1
f(2) = - 2 * f(1) + 3 = - 2 * (-1) + 3 = 2 + 3 =
5
The correct result would be f(2) = 5.</span>
