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Alex Ar [27]
3 years ago
7

A(c−b)=d solve for c

Mathematics
1 answer:
Rainbow [258]3 years ago
4 0

Answer:

The solution to this equation could not be determined.

Step-by-step explanation:

Simplifying

a(c + -1b) = d

Reorder the terms:

a(-1b + c) = d

(-1b * a + c * a) = d

(-1ab + ac) = d

Solving

-1ab + ac = d

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Combine like terms: d + -1d = 0

-1ab + ac + -1d = 0

The solution to this equation could not be determined.

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A CD usually sells for $18.00. If the CD is 30% off, and sales tax is 6%, what is the total price of the CD, including tax?
natali 33 [55]
Ok first find out what it will cost after the 30% discount

18*.30=
$5.40 discount 
$18.00-$5.40=
$12.60
Now lets figure out the sales tax
$12.60*.06=
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total price including tax is $13.36
6 0
3 years ago
I need help from uh all..​
DanielleElmas [232]

Answer:

Step-by-step explanation:

Given expression is,

\text{cot}A=\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})

To prove this identity we will take the right side of the identity,

\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})=\frac{1}{2}(\frac{1}{\text{tan}\frac{A}{2}}-tan\frac{A}{2})

                         =\frac{1}{2}(\frac{1-\text{tan}^2\frac{A}{2}}{tan\frac{A}{2}})

                         =\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]

                         =\frac{1}{2}(\frac{2}{\text{tan}A} ) [Since \text{tan}A=\frac{2\text{tan}\frac{A}{2}}{1-\text{tan}^2\frac{A}{2}}]

                         = cot A

Hence right side of the equation is equal to the left side of the equation.

3 0
3 years ago
If the trapezoid on the grid below is translated by using the rule (x,y)-> (x-4,y-3) what will be the coordinates of B’?
vesna_86 [32]

Answer:

B'(3, 5)

Step-by-step explanation:

Rule for the translation of a point (x, y) by 'h' units left and 'k' units upwards,

(x, y) → (x - h, y + k)

If h = 4 and k = 3,

(x, y)\rightarrow(x-4,y+3)

Following this rule coordinates of the image point of B will be,

B(7, 2) → B'(7 - 4, 2 + 3)

           → B'(3, 5)

Therefore, coordinates of the image point B' will be,

B'(3, 5)

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