3 years ago

Help will give crown

Mathematics

2 answers:

IrinaVladis [17]3 years ago

5 0

Answer:

the answer of the question is C because 1/2=.5

iris [78.8K]3 years ago

3 0

The answer is D. because 5/9 equals 0.5 repeating

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In the figure, PQ is parallel to RS. The legth of RP is 4 cm; the length of PT is 16 cm; the length of QT is 20 cm. What is the

Studentka2010 [4]

4/16 = SQ/20

SQ = (4*20) / 16 = 5 cm

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2 years ago

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A certain forest covers an area of 1700 km^2. Suppose that each year this area decreases by 3.25%. What will the area be after 6

Olenka [21]

y= 1700 (1- .0325) ^15

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Hope this helps!

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3 years ago

PLEASE HELP -Given the graph of rectangle QUAD and its reflection.

V125BC [204]

Q is located at (-5,2)
Q" is located at (6,2)
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we need to find out where on the X axis it was reflected.
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3 years ago

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Vika [28.1K]

What does this even mean

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2 years ago

A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,

zloy xaker [14]

Answer:

$t=-20ln\left(\dfrac{1}{3}\right)$

Step-by-step explanation:

The relationship between A, the area of the glacier in square kilometers, and t, the number of years the glacier has been melting, is modeled by the equation.:

$A=45e^{-0.05t}$

We want to determine the value of t for which the area, A(t)=15 square kilometers.

$15=45e^{-0.05t}\\$Divide both sides by 45\\\dfrac{15}{45} =\dfrac{45e^{-0.05t}}{45}\\\dfrac{1}{3}=e^{-0.05t}\\$Take the natural logarithm of both sides\\ln\left(\dfrac{1}{3}\right)=ln\left(e^{-0.05t}\right)\\ln\left(\dfrac{1}{3}\right)=-0.05t\\$Divide both sides by -0.05$\\t=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05} \\=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05}\\t=-20ln\left(\dfrac{1}{3}\right)$

Therefore, the time for which the area will be 15 sqyare kilometers is:

-20 ln(1/3) years.

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3 years ago