Answer: I think its B instead of A
Answer:
Step-by-step explanation:
♨Rage♨
Differences:
If the a≠1, then instead of finding two numbers that when multiplied equal c and when added equal b (which is the a=1 situation), you are looking for two numbers which when multiplied equal ac and add up to be b.
When finding the two numbers for a≠1, you cannot just plug the two numbers into (x+__)(x+__), you have to extend the b term into those two numbers.
After extending the b term into the two terms, you then have to group them and take out the GCF's unlike in an a=1 situation.
Similarities:
The first step for both is finding two terms which equal b if added.
Once factored, you have to set the factored sections to zero if you wish to find the solutions.
Before finding the two terms which equal b if added, you should take out any GCF's from the overall equation.
What is the relationship between v(t), x(t), and a(t)? I assume that v(t) is a velocity and x(t) is distance traveled in relation to v(t) and a(t) is the acceleration in relation to v(t). So . . .
x(t) =
∫v(t)dt
= ∫(8t + 25)dt = 4
+ C
a(t) = d/dt(v(t)) = d/dt(8t+25) = 8
