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babymother [125]
3 years ago
15

There are....... section incpu​

Computers and Technology
1 answer:
adell [148]3 years ago
3 0

Explanation:

The CPU is made up of three main components, the control unit , the immediate access store and the arithmetic and logic unit .

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Write a program which promptsuser to enter an integer value. Using while loop print the valuesfrom
tino4ka555 [31]

Answer:Following is the c++ code for the problem:

#include <iostream>

using namespace std;

int main() {

   int number;

   cout<<"Enter the number"<<endl;

   cin>>number;

   int i=0,c=0,odd[500];

   while(i<=number)//loop for printing the numbers form 0 to number.

   {

       cout<<i<<" ";

       if(i%2!=0)// storing in the odd array if the number is odd.

       {

           odd[c++]=i;//storing odd numbers..

       }

       i++;

   }

   cout<<endl;

   i=0;

   cout<<"The odd numbers are "<<endl;

   while(i<c)//loop to print the odd numbers.

   {

       cout<<odd[i]<<" ";

       i++;

   }

   cout<<endl<<"The prime numbers are "<<endl;

   i=0;

   int sum=0;

   

   while(i<c)//loop to print the prime numbers..

   {

       int div=2;

       while(div<odd[i])

       {

           if(odd[i]%div==0)

           break;

           div++;

       }

       if(div==odd[i])

      {

           cout<<odd[i]<<" ";

           sum+=odd[i];//updating the sum..

      }

       i++;

   }

   cout<<endl<<"The sum of odd prime numbers is "<<sum<<endl;//printing the sum..

return 0;

}

Output :

Enter the number

49

0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49  

The odd numbers are  

1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49  

The prime numbers are  

3 5 7 11 13 17 19 23 29 31 37 41 43 47  

The sum of odd prime numbers is 326 .

Explanation:

First I have printed the values from 0 to n and i have taken an array to store odd numbers.After that i have printed the odd values.And after that i have printed prime numbers among the odd numbers and their sum. These all operations are done using while loop.

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3 years ago
NO LINKS OR SPAMS THEY WILL BE REPORTD<br><br> Click here for 50 points
storchak [24]

Answer:

I clicked bro

Explanation:

What now?

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Laptop computers, personal digital assistants, and cellular phones were all readily accepted and diffused in U.S. markets where
astra-53 [7]

Answer: Compatibility

Explanation:

 According to the question, the given products are offering compatibility with the customers needs and the priorities of the consumers. The customers comparability means the degree of the product that fit between customers expectation and the capability of serving by the operation team.

The customers expectation mainly reflected both the present and the past evaluation of the products and the user experience. The compatibility of the customers needs is to meet the quality, value  and the service of the product.

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The graphic shows a cause and effect organizational aid.
nika2105 [10]

Answer:

gets good grades

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Write a method drivingCost() with input parameters drivenMiles, milesPerGallon, and dollarsPerGallon, that returns the dollar co
aleksklad [387]

Answer:

public static double drivingCost(int drivenMiles, double milesPerGallon,double dollarsPerGallon){

       return (drivenMiles/milesPerGallon)*(dollarsPerGallon);

   }

Find a complete java program that prompts the user to enter this values and the calls this Method in the explanation section.

Explanation:

<em>import java.util.Scanner;</em>

<em>public class ANot {</em>

<em>    public static void main(String[] args) {</em>

<em>    Scanner in = new Scanner(System.in);</em>

<em>        System.out.println("Please Enter the Driven Miles");</em>

<em>        int drivenMiles = in.nextInt();</em>

<em />

<em>        System.out.println("Please Enter the Your fuel consumption in miles/gallon");</em>

<em>        double milesPerGallon = in.nextDouble();</em>

<em />

<em>        System.out.println("Please Enter the cost of fuel in Dollars/gallon");</em>

<em>        double dollarsPerGallon = in.nextDouble();</em>

<em />

<em>        double dollarCost = drivingCost(drivenMiles,milesPerGallon,dollarsPerGallon);</em>

<em>        System.out.println("The Total Cost in Dollars is "+dollarCost);</em>

<em>        }</em>

<em>    public static double drivingCost(int drivenMiles, double milesPerGallon,double dollarsPerGallon){</em>

<em />

<em>        return (drivenMiles/milesPerGallon)*(dollarsPerGallon);</em>

<em>    }</em>

<em>}</em>

8 0
3 years ago
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