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levacccp [35]
3 years ago
8

There are four types of characteristics attributed to a flow: reliability, delay, jitter, and bandwidth. Explain how each of the

se is related to Quality of Service.
Computers and Technology
1 answer:
sergeinik [125]3 years ago
4 0

Answer and Explanation:

Reliability is important because if the service lacks  lacks reliability this could mean losing a packet or acknowledgement which then requires retransmission.

Delay can be tolerable in different degrees by applications, for example online chatting or conferences need to have the minimum delay possible.

Jitter is the variation in delay for packets belonging to the same flow.

High Jitter: difference between delays is large

Low jitter: difference between delays is small.

Bandwidth depends on the application. In video conferences, for example, there is a need to send million of bits per second to refresh a colour screen while sending a email may not reach even a million.

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knowledge contributes vitally to the development of __________ memory, or recollections of personally experienced events that oc
Anettt [7]

Answer:

Episodic

Explanation:

Episodic memory are memory that enables a person to remember most important event that happen to them, which are unique to them and are tied to a specific time and place.

It can be the memory of every day events or experiences that occured to the person at a particular time and date.

Example:

Episodic memory is when an individual remember his /her date of birth or specific events and experiences.

Therefore Knowledge contributes vitally to the development of EPISODIC memory, or recollections of personally experienced events that occurred at a specific time and place.

5 0
3 years ago
A team member who feels uncomfortable when disagreeing with another team member is likely from a(n) _______(fill in the blank) c
Delvig [45]

collectivistic culture

7 0
3 years ago
Identify a major drawback of browsing web pages on mobile devices.
Pavlova-9 [17]
It was way too much of a drawback
5 0
3 years ago
g Suppose the vertex data is stored in an array named verts and each vertex uses a list to store the coordinates. Write the code
kodGreya [7K]

Answer:

function createAndFillBufferObject(gl, data) {

 var buffer_id;

 // Create a buffer object

 buffer_id = gl.createBuffer();

 if (!buffer_id) {

   out.displayError('Failed to create the buffer object for ' + model_name);

   return null;

 }

 // Make the buffer object the active buffer.

 gl.bindBuffer(gl.ARRAY_BUFFER, buffer_id);

 // Upload the data for this buffer object to the GPU.

 gl.bufferData(gl.ARRAY_BUFFER, data, gl.STATIC_DRAW);

 return buffer_id;

}

3 0
3 years ago
write a java program that prompts the user to enter scores (each number an integer from 0 to 10) and prints the following output
Vladimir [108]

Answer:

Explanation:

The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int count = 0;

       int highest, lowest;

       ArrayList<Integer> myArr = new ArrayList<>();

       while (true) {

           System.out.println("Enter a number [0-10] or -1 to exit");

           int num = in.nextInt();

           if (num != -1) {

               if ((num >= 0) && (num <= 10)) {

                   count+= 1;

                   myArr.add(num);

               } else {

                   System.out.println("Wrong Value");

               }

           } else {

               break;

           }

       }

       if (myArr.size() > 3) {

           highest = myArr.get(0);

           lowest = myArr.get(0);

           for (int x: myArr) {

               if (x > highest) {

                   highest = x;

               }

               if (x < lowest) {

                   lowest = x;

               }

           }

           System.out.println("Number of Elements: " + count);

           System.out.println("Highest: " + highest);

           System.out.println("Lowest : " + lowest);

       } else {

           System.out.println("Number of Elements: " + count);

           System.out.println("No Highest or Lowest Elements");

       }

   }

}

4 0
2 years ago
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