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sp2606 [1]
3 years ago
10

Consider a regular hexagon centered at (3,4). Describe a rotation that

Mathematics
1 answer:
Ne4ueva [31]3 years ago
3 0

Answer:

36- degree rotation m8

Step-by-step explanation:

mark me brainliest :)

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Select the correct answer.
Crazy boy [7]

Answer:

16

Step-by-step explanation:

to get from 3/4 to 12/x you gotta multiple 3 times 4 which is 12 so the bottom multiple that by 4 also which 4 x 4 is 16

3 0
3 years ago
Read 2 more answers
Find the volume of the pyramid.
Anon25 [30]
V=7 with the little 3
6 0
3 years ago
A 25 ft. ladder resting against the side of a building forms a right triangle with the ground. The bottom of the ladder is 7 ft.
ruslelena [56]

Answer:

The correct answer is 24

Step-by-step explanation:

to solve this you will need to use the pathagreom theorum

a^{2}+b^{2}=c^{2}

A= one side lenth

B= the secons side lenth

C= hypotnuse

It is helpfull to draw out the situation

you know that the latter is 25 ft, that is your hypotnuse

you also know that the 7 ft away from the base of the building is one of the side lenths, lets call it side a

so plug the numbers into the equation

7^2 + b^2 = 25 ^2

you leave b^2 alone because that is the side you are trying to find

now square 7 and 25 but leave b^2 alone

49 + b^2 = 625

now subtract 49 from both sides

b^2 = 576

now to get rid of the square of b you have to do the opposite and square root both sides removing the square of the B and giving you the answer of..........

B= 24

Hope this helped!! I tryed to explain it as simpil as possiable

6 0
2 years ago
Read 2 more answers
*In ∆ABC, on the extension of the side BC , draw a line segment CD ≅ CA . Draw the segment AD . The line segment CE is the angle
Leya [2.2K]

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Step-by-step explanation:

In ∆ABC

  • On the extension of the side BC , draw a line segment CD ≅ CA
  • Draw the segment AD
  • The line segment CE is the angle bisector of ∠ACB
  • The line segment CF is the median towards AD in ∆ ACD

We want to prove that CF ⊥ CE

Look to the attached figure

In Δ ABC

∵ CE is the bisector of angle ACB

∴ ∠ACE ≅ ∠BCE

In Δ ACD

∵ CA = CD

∴ Δ ACD is an isosceles triangle

∵ AD is the median towards AD

- In any isosceles triangle the median from a vertex to its opposite

  side bisects this vertex

∴ AD bisects ∠ACD

∴ ∠ACF ≅ ∠DCF

∵ BCD is a straight segment

∵ CE , CA , CF are drawn from point C

∴ m∠BCE + m∠ACE + m∠ACF + m∠DCF = 180°

∵ m∠ACE ≅ m∠BCE

∵ m∠ACF ≅ m∠DCF

- Replace m∠BCE by m∠ACE and m∠DCF by m∠ACF

∴ m∠ACE + m∠ACE + m∠ACF + m∠ACF = 180°

∴ 2 m∠ACE + 2 m∠ACF = 180°

- Divide all terms by 2

∴ m∠ACE + m∠ACF = 90°

∴ EC ⊥ CF

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Learn more:

You can learn more about perpendicular lines in brainly.com/question/11223427

#LearnwithBrainly

7 0
3 years ago
Karen is buying pens and pencils for the new school year. She wants to have no more than 25 writing utensils in all. She also wa
bezimeni [28]
For this case, the first thing we must do is define variables.
 We have then:
 x: number of pens
 y: number of pencils
 We now write the system of inequations:
 x + y  \leq  25

y  \geq  (x - 3) ^ 2

 The solution to the system of inequations is given by the shaded region.
 Note: see attached image.

3 0
3 years ago
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