I think is D , hope i answer fast enough haha :D
Answer:
Step-by-step explanation:
In order to write the series using the summation notation, first we need to find the nth term of the sequence formed. The sequence generated by the series is an arithmetic sequence as shown;
4, 8, 12, 16, 20...80
The nth term of an arithmetic sequence is expressed as Tn = a +(n-1)d
a is the first term = 4
d is the common difference = 21-8 = 8-4 = 4
n is the number of terms
On substituting, Tn = 4+(n-1)4
Tn = 4+4n-4
Tn = 4n
The nth term of the series is 4n.
Since the last term is 80, L = 4n
80 = 4n
n = 80/4
n = 20
This shows that the total number of terms in the sequence is 20
According to the series given 4 + 8 + 12 + 16 + 20+ . . . + 80
, we are to take the sum of the first 20terms of the sequence. Using summation notation;
4 + 8 + 12 + 16 + 20+ . . . + 80 =
Answer:
AM=6
Step-by-step explanation:
Parallelogram has two equal parallel sides
This implies that PM parallel and equal to ON
Also, MN is parallel and equal to OP
Since the diagonals bisect each other it implies that AM=AO and NP=AP
From the question, AO=6
Therefore,AM=6
If I am reading the equations correctly, they are:
5x - 14 = 3x AND 7x + 12 = x - 6
If this is correct, the first one would be worked out like this:
5x (- 5x) - 14 = 3x (- 5x)
- 14 = - 2x
- 14 (/ - 2) = - 2x (/ - 2)
7 = x
The second would be worked out like this:
7x + 12 (+ 6) = x - 6 (+ 6)
7x + 18 = x
7x (- 7x) + 18 = x (- 7x)
18 = - 6x
18 (/ - 6) = - 6x (/ - 6)
- 3 = x
I hope this is what you are looking for :)