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marin [14]
4 years ago
5

Anyone who knows this please help me out

Mathematics
1 answer:
leva [86]4 years ago
5 0
1 unit left and reflection across x axis
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Evaluate the expression: 15f-60 if f=5
rosijanka [135]

Answer:

15

Step-by-step explanation:

15f-60=15×5-60=75-60=15

6 0
3 years ago
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lola just received a promotion at work now earns $18 per hour. she writes the equation y=18x to represent her total earnings ,y,
aliya0001 [1]

Answer:

Step-by-step explanation:

Just took the test

5 0
3 years ago
Which decimal is greater: 0.347 or 0.437?
trapecia [35]

Answer:

0.437

Step-by-step explanation:

Decimals are read the same as whole numbers, starting with the first digit, which is the largest, to the right. So, to find the larger decimal you need to look at the first digit. If this digit is the same then continue to the right until there is a difference in the number. In this case, the first digit is different. Therefore, whichever has the larger first digit must be the greater one. Since 4 > 3, 0.437 must be greater than 0.347.

5 0
2 years ago
I need help knowing how to show the work and how to get the answer and the answer it self
Morgarella [4.7K]
Find the separate areas.

We have a triangle with base 5 cm and height 5 cm, calculate the area:

\sf A=\dfrac{1}{2}bh

Plug in what we know:

\sf A=\dfrac{1}{2}(5)(5)

Multiply:

\sf A=12.5~cm^2

Now for the two quarter circles, we know that if we put these two together we will end up with a semi-circle with radius 5 cm. The formula for the area of a circle is:

\sf A=\pi r^2

A semi-circle is half of a whole circle, so the formula for the area of it must be:

\sf A=\dfrac{1}{2}\pi r^2

Now plug in what we know(use 3.14 to approximate for pi):

\sf A\approx\dfrac{1}{2}(3.14)(5)^2

Simplify the exponent:

\sf A\approx\dfrac{1}{2}(3.14)(25)

Multiply:

\sf A\approx 39.25~cm^2

Now add this to the area of the triangle to find the approximate area of the entire figure(round to the nearest tenth):

\sf 39.25+12.5=\boxed{\sf 51.8~cm^2}
4 0
3 years ago
2x+3y=0 and x+2y=-1 <br> Solve by substitution
dmitriy555 [2]

Answer:

The solution of the given equations is (-3,2)

Step-by-step explanation:

<u>Step:1</u>

The Given equations are 2 x+3 y=0 .......(1)

                                          x+2 y-1 =0.........(2)

<u>Step 2:-</u>

Solving<u> </u>both equations by using substitution method

multiply equation (2) with number '2' ,  

2 x+4 y-2=0.......(3)

subtracting the equations (1) and (3) and cancelled 'x' terms

we get 3y-4y=0-2

y=2

<u>Step 3:</u>-

substitute y= 2 in equation (1) we get

2 x+3 y=0

2 x+3(2)=0

2 x=-6

x=-3

<u>Final answer</u>:-

The solution of the given equations is (-3,2)

8 0
4 years ago
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