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kap26 [50]
3 years ago
15

SOMEONE PLEASE HELP ASAP IM IN A TEXT NO EXPLANAION NEEDED JUST THE FUNCTION!!THANK YOU SO MUCH :)

Mathematics
1 answer:
Lynna [10]3 years ago
3 0

Answer:

\frac{-1}{4} x^{2}

\frac{-1}{4} g(x)

Step-by-step explanation:

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Haley and her 4 friends decide to go out to dinner at Applebee's. The bill for their table came to $65.30. If they want to split
MAXImum [283]

Answer:

$13.06

Step-by-step explanation:

There are five people so 65.30/5 = 13.06

8 0
2 years ago
The sum of two numbers is 50 and the difference is 12. What are the numbers?
Strike441 [17]

Answer:

The two numbers are 31 and 19

Step-by-step explanation:

Let x and y be the numbers

x+y = 50

x-y = 12

Add the two equations together

x+y = 50

x-y = 12

-----------------

2x +0y = 62

Divide by 2

2x/2 = 62/2

x = 31

Now find y

31+y = 50

Subtract 31

y = 50-31

y = 19

3 0
3 years ago
Read 2 more answers
The length of a lacrosse field is 15 yards less than twice the width, and the perimeter in 270 yards. The defensive area of the
sammy [17]

The defensive area is 510 square yards

Step-by-step explanation:

Let L be the length of the rectangle

and

W be the width

According to given statement

L = 2W-15

Perimeter = 270

P = 2W+2L\\270 = 2W + 2(2W-15)\\270 = 2W + 4W -30\\270 +30 = 6W\\6W = 300

Dividing both sides by 6

\frac{6W}{6} =\frac{300}{6}\\W = 50\ yards\\\\and\\L = 2(50) -15\\= 100-15\\=85\ yards

We have to find the area first to find the defensive area

So,

Area = L* W\\= 85 * 50\\=4250\ square\ yards

Defensive area = 3/25 of total area

So,

=\frac{3}{25}*4250\\=3 *170\\=510\ square\ yards

Hence,

The defensive area is 510 square yards

Keywords: Area, Rectangle

Learn more about area at:

  • brainly.com/question/12497249
  • brainly.com/question/1238144

#LearnwithBrainly

5 0
3 years ago
Over her 17 day winter break, Lindsay want to read the last book in the Harry Potter seriees, which has 759 pages. If she reads
Alex Ar [27]

Answer: Yes, she will finish before winter break is over.

Explanation:

Since we have given that

Number of days in winter break = 17

Number of pages she read in each day = 75

Number of pages in the Harry Potter series she wants to read = 759

Now, we'll use unitary method,

in 1 day , she read = 75 pages

in 17 days , she read is given by

17\times 75=1275\text{ pages}

and 759 pages is less than 1275 pages.

So, she will finish before winter break is over.

7 0
3 years ago
A bagel shop wants to estimate their daily demand for their popular poppy seed bagel. The shop owner determined that the daily d
forsale [732]

Answer:

Probability that the number of poppy seed bagels sold on a particular day exceeds 400 is 0.0475.

Step-by-step explanation:

We are given that the shop owner determined that the daily demand follows the normal probability model with mean 300 bagels and standard deviation 60.

<em>Let X = daily demand of poppy seed bagels</em>

The z-score probability distribution for normal distribution is given by;

           Z = \frac{ X-\mu}{\sigma}} }  ~ N(0,1)

where, \mu = mean bagels = 300

            \sigma = standard deviation = 60

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the number of poppy seed bagels sold on a particular day exceeds 400 is given by = P(X > 400)

 P(X > 400) = P( \frac{ X-\mu}{\sigma}} } > \frac{ 400-300}{60}} } ) = P(Z > 1.67) = 1 - P(Z \leq 1.67)

                                                   = 1 - 0.95254 = <u>0.0475</u>                       

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.67 in the z table which has an area of 0.95254.</em>

Hence, the probability that the number of poppy seed bagels sold on a particular day exceeds 400 is 0.0475.

3 0
3 years ago
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