1. y < -x - 5......(-3,-4)
2. 5x - 3y < = 15.....all of ur answers satisfy this inequality
P=2(L+W)
if given one side and the perimiter
(P/2)-L=W
(P/2)-W=L
Third term = t3 = ar^2 = 444 eq. (1)
Seventh term = t7 = ar^6 = 7104 eq. (2)
By solving (1) and (2) we get,
ar^2 = 444
=> a = 444 / r^2 eq. (3)
And ar^6 = 7104
(444/r^2)r^6 = 7104
444 r^4 = 7104
r^4 = 7104/444
= 16
r2 = 4
r = 2
Substitute r value in (3)
a = 444 / r^2
= 444 / 2^2
= 444 / 4
= 111
Therefore a = 111 and r = 2
Therefore t6 = ar^5
= 111(2)^5
= 111(32)
= 3552.
<span>Therefore the 6th term in the geometric series is 3552.</span>
Because two horizontal lines never intersect.
<h3>
Answer: 11/50</h3>
Explanation:
This may seem like a trick question, but it's not. Your teacher simply wants to know how many times you got blue out of the number of times total. The numerator is the number of blue. The denominator is the number of total tries. The fraction 11/50 cannot be reduced because 11 and 50 share no common factors other than 1.
Notes:
- 11/50 = 0.22 = 22%
- The answer above applies to experimental probability only. The theoretical probability is likely different. We don't have enough info to compute the theoretical probability.
