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Anni [7]
3 years ago
9

Maria mixes \frac{1}{4} cup white sugar and \frac{2}{3} cup brown sugar to make a topping for some muffins. She uses \frac{1}{12

} cup of the mixture to top each muffin. How many muffins can she top?
Mathematics
1 answer:
Hoochie [10]3 years ago
3 0

Answer: 11 muffins

Step-by-step explanation:

Since Maria mixes 1/4 cup white sugar with 2/3 cup brown sugar, this will give us a mixture of:

= 1/4 + 2/3

= 3/12 + 8/12

= 11/12

Ww are then told that she uses 1/12 cup of the mixture to top each muffin. Therefore, the number of muffins that she can top will be:

= 11/12 ÷ 1/12

= 11/12 × 12/1

= 12

She can top 11 muffins.

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Which of the following are solution to the inequality below -4w - 2 < -38
FromTheMoon [43]

Answer:

w > 9

Step-by-step explanation:

Solve the inequality by using inverse operations.

-4w - 2 < -38

-4w < -36

w > 9

Like solving equations, inequalities should be solved using inverse operations. However, unlike equations, when you divide or multiply by a negative the sign changes.

8 0
3 years ago
Please Help!!! Evaluate the following <br><br> 2/((3-(3-1))*3-1)
antiseptic1488 [7]
2/ 3 - (3 - 1) * 3 - 1 = -4
Simplify
= 2/-4
which is
= -2/4 
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= -1/2
6 0
3 years ago
Convert the mixed number to an improper fraction. 2 7/10 A.14/10 B.27/10 C.34/10 D.37/10
boyakko [2]
So, to make a mixed number into an improper fraction, you have to multiply the whole number by the denominator and then add the numerator o that number.
2 and 7/10:
2x10=20+7=27/10!
<u>The answer would be B!</u>
I hope this helps!
7 0
3 years ago
Read 2 more answers
AC is tangent to circle O at A. The Diagram is not to scale.
statuscvo [17]

Answer:

  • B. 64°

Step-by-step explanation:

<u>Given:</u>

  • mBY = 52°

<u>Inscribed angle measure is half the intercepted arc:</u>

  • m∠BAY = 1/2(52°) = 26°

<u>The angle between the diameter and tangent is right angle:</u>

  • m∠BAC = 90°

<u>According to angle addition postulate:</u>

  • m∠YAC = m∠BAC - m∠BAY
  • m∠YAC = 90° - 26° = 64°

Correct choice is B

7 0
2 years ago
Read 2 more answers
Suppose that the mean water hardness of lakes in Kansas is 425 mg/L and these values tend to follow a normal distribution. A lim
tino4ka555 [31]

Answer:

The mean water hardness of lakes in Kansas is 425 mg/L or greater.

Step-by-step explanation:

We are given the following data set:

346, 496, 352, 378, 315, 420, 485, 446, 479, 422, 494, 289, 436, 516, 615, 491, 360, 385, 500, 558, 381, 303, 434, 562, 496

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{10959}{25} =438.36

Sum of squares of differences = 175413.76

S.D = \sqrt{\dfrac{175413.76}{24}} = 85.49

Population mean, μ = 425 mg/L

Sample mean, \bar{x} = 438.36

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 85.49

First, we design the null and the alternate hypothesis

H_{0}: \mu \geq 425\text{ mg per Litre}\\H_A: \mu < 425\text{ mg per Litre}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{438.36 - 425}{\frac{85.49}{\sqrt{25}} } = 0.7813

Now, t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.7108

Since,                        

The calculated t-statistic is greater than the critical value, we fail to reject the null hypothesis and accept it.

Thus, the mean water hardness of lakes in Kansas is 425 mg/L or greater.

6 0
3 years ago
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