Answer:
Probability that at least one head appears is
Step-by-step explanation:
Given : Three fair quarters are tossed, and a tail appears on at least one of them.
To find : What is the probability that at least one head appears?
Solution :
When three fair quarters are tossed the sample form is
According to question,
In a sample space a tail appears on at least one of them.
i.e. Total outcomes is
Favorable outcome is getting at least one head appears
i.e. Favorable outcome is
Probability that at least one head appears is
Therefore, Probability that at least one head appears is
Answer:
24 m²
Step-by-step explanation:
At = Ap/2 = 48m²/2 = 24 m²
Answer: 180=x
Step-by-step explanation:
180=100+2x+14
180=2x+114
-114 -114
36=2x
÷2 ÷2
18=x
Y=mx+b
b is your y intercept so it must be 2 if i am correct
m is the number before x
so it would be i think
y = 1x+2
Hope This Helps!!!
-7(4-2)+1=15-7x
-7 x 2 + 1 = 15 - 7x
-14 + 1 = 15 -7x
-13 -15= -7x
-28 = -7x
-28 / -7 = x
x=4
3x - 54 = 160 >I just flipped the equation
3x - 54 (+54) = 160 (+54) added 54 each
3x = 160
3x/3 = 160/3 >divided 3 to each side
x = 160/30
or 53.33333333333333333~