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Rasek [7]
3 years ago
8

Solve the system by elimination. First, clear the denominators.

Mathematics
1 answer:
NARA [144]3 years ago
7 0

I am not smart ether lol

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9 ten thousands scientific notation
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0.0009) is 9x10^-4

Step-by-step explanation:

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fourteen boxes of candle were sold for 91.00.each box contains 5 candles. what is the cost of 1 candle
Gwar [14]
Multiply 14 times 91 then divide by 14 times 5.
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6 0
3 years ago
Give the domain and range of the relation.<br> y=(x+4)^2-4
Westkost [7]

Answer:

The domain is the interval  (-∞,∞)

The range is the interval [-4,∞)

Step-by-step explanation:

we have

y=(x+4)^2-4

This is the equation of a vertical parabola in vertex form

The vertex is the point (-4,-4)

The parabola open upward (because the leading coefficient is positive)

The vertex represent a minimum

The domain is the interval  (-∞,∞)

so

The domain is all real numbers

The range is the interval [-4,∞)

y\geq -4

so

The range is all real numbers greater than or equal to -4

7 0
3 years ago
Sienna has 5 3/4 pounds of grapes. She eats 1/8 pound and gives 2 1/2 pounds to her brother. How many pounds of grapes does Sien
miskamm [114]

The pounds of grapes left with seinna is 3.125 or \frac{25}{8} pounds

<h3><u>Solution:</u></h3>

Given that Sienna has 5\frac{3}{4} pounds of grapes

She eats \frac{1}{8} pound and gives 2\frac{1}{2} pounds to her brother

<em><u>To find: pounds of grapes left with seinna</u></em>

We can find the pounds of grapes left with seinna by subtracting the pounds of grapes she ate and pounds of grapes she gave to brother from the total pounds of grapes she had

Pounds of grapes left with seinna = total pounds of grapes - pounds of grapes she ate - pounds of grapes she gave to brother

\text {total pounds of grapes }=5 \frac{3}{4}=\frac{4 \times 5+3}{4}=\frac{23}{4}

\text {pounds of grapes she ate }=\frac{1}{8}

\text {pounds of grapes she gave to brother }=2 \frac{1}{2}=\frac{2 \times 2+1}{2}=\frac{5}{2}

<em><u>Substituting the values we get,</u></em>

\text {Pounds of grapes left with seinna }=\frac{23}{4}-\frac{1}{8}-\frac{5}{2}

\text { Pounds of grapes left with seinna }=5.75-0.125-2.5=3.125

Thus the pounds of grapes left with seinna is 3.125 or \frac{25}{8} pounds

5 0
3 years ago
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