Answer:
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Step-by-step explanation:
Given
Volume of a box = length × breadth × height= l×b×h
In this case the box have a square base. i.e l=b
Volume V = l^2 × h
The surface area of a square box
S = 2(lb+lh+bh)
S = 2(l^2 + lh + lh) since l=b
S = 2(l^2 + 2lh)
Given that the box is open top.
S = l^2 + 4lh
And Surface Area of the box is 1200cm^2
1200 = l^2 + 4lh ....1
Making h the subject of formula
h = (1200 - l^2)/4l .....2
Volume is given as
V = l^2 × h
V = l^2 ×(1200 - l^2)/4l
V = (1200l - l^3)/4
the maximum point is at dV/dl = 0
dV/dl = (1200 - 3l^2)/4
dV/dl = (1200 - 3l^2)/4 = 0
3l^2= 1200
l^2 = 1200/3 = 400
l = √400
I = 20cm
Since,
h = (1200 - l^2)/4l
h = (1200 - 20^2)/4×20
h = (800)/80
h = 10cm
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Answer:
269.6 square centimeters
Step-by-step explanation:
<u><em>The correct question is</em></u>
The diagram shows the net of a juice box. the box is a rectangular prism. what is the surface area of the juice box? 6.4 cm 4 cm 10.5 cm
we know that
The surface area of a rectangular prism is equal to
where
B is the area of the base
P is the perimeter of the base
H is the height of the prism
we have
<em>Find the area of the base B</em>
substitute the given values
<em>Find the perimeter of the base P</em>
substitute the given values
<em>Find the surface area</em>
substitute
At x = 0, y-coordinate is at -4 so that means f(0) = -4
Now for f(x) = 4, we need to find any x-coordinates such that y-coordinates is 4.
There are two possible answer: x = -8 and x = 8
So x = -8, 8
Hope this helps.
Step-by-step explanation:
Given,
a=3,b=2,c=5
a)a(b+c)
=3(2+5)
=3×7
=21.
B)2ac^2
=2×3×(5)^2
=6×25
=150
Answer:
I will answer in a general way because the options are not given.
We know that the area of model A is smaller than the area of model B.
For model A, we have 72 shaded sections, out of 100.
Then the quotient of model A is:
72/100 = 0.72
For model B we have 10 sections, and x shaded ones.
Because model B is greater than model A, we know that:
x/10 should be larger than 72/100
then we have the inequality:
x/10 > 0.72
x > 0.72*10
x > 7.2
And we can not have more than 10 shaded sections (because there is a total of 10 sections) then:
10 ≥ x > 7.2
Then x can be any whole number in that interval.
the possible values of x are:
x = 8
x = 9
x = 10
