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Galina-37 [17]
3 years ago
11

Write the integer represented by H. List its opposite and absolute value.

Mathematics
1 answer:
musickatia [10]3 years ago
4 0

Answer:

The integer represented by H is -2

Its opposite is 2 and the absolute value is also 2

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Which of the following relationships is a direct variation?
mafiozo [28]

Answer:Well All i know is that the answer is not C I'm sorry I dont know the correct answer but I know for a fact that the answer isn't C

Step-by-step explanation:

4 0
4 years ago
Graph the linear equations in three points: -x-2y=-10
dmitriy555 [2]

Answer:

Step-by-step explanation:

Rewrite -x-2y= -10 as  -2y= x - 10 and then as y = (-1/2)x + 5.

Then choose any 3 x values and find the corresponding y values using this formula.  For example:

 x     y = (-1/2)x + 5              (x, y)

-----   --------------------            ---------

 0                   5                    (0, 5)

-4       (-1/2)(-4) + 5 = 7         (-4, 7)

  6      (-1/2)(6) + 5 = 2          (6, 2)

Plot these three points and then draw a line through them.  

4 0
3 years ago
Read 2 more answers
Verify that the conclusion of Clairaut’s Theorem holds, that is, uxy = uyx, u=tan(2x+3y)
choli [55]

Answer: Hello mate!

Clairaut’s Theorem says that if you have a function f(x,y) that have defined and continuous second partial derivates in (ai, bj) ∈ A

for all the elements in A, the, for all the elements on A you get:

\frac{d^{2}f }{dxdy}(ai,bj) = \frac{d^{2}f }{dydx}(ai,bj)

This says that is the same taking first a partial derivate with respect to x and then a partial derivate with respect to y, that taking first the partial derivate with respect to y and after that the one with respect to x.

Now our function is u(x,y) = tan (2x + 3y), and want to verify the theorem for this, so lets see the partial derivates of u. For the derivates you could use tables, for example, using that:

\frac{d(tan(x))}{dx} = 1/cos(x)^{2} = sec(x)^{2}

\frac{du}{dx}  =  \frac{2}{cos^{2}(2x + 3y)} = 2sec(2x + 3y)^{2}

and now lets derivate this with respect to y.

using that \frac{d(sec(x))}{dx}= sec(x)*tan(x)

\frac{du}{dxdy} = \frac{d(2*sec(2x + 3y)^{2} )}{dy}  = 2*2sec(2x + 3y)*sec(2x + 3y)*tan(2x + 3y)*3 = 12sec(2x + 3y)^{2}tan(2x + 3y)

Now if we first derivate by y, we get:

\frac{du}{dy}  =  \frac{3}{cos^{2}(2x + 3y)} = 3sec(2x + 3y)^{2}

and now we derivate by x:

\frac{du}{dydx} = \frac{d(3*sec(2x + 3y)^{2} )}{dy}  = 3*2sec(2x + 3y)*sec(2x + 3y)*tan(2x + 3y)*2 = 12sec(2x + 3y)^{2}tan(2x + 3y)

the mixed partial derivates are equal :)

7 0
3 years ago
Use the long division method to find the result when 3.23 + 8x2 + 9x + 10 is<br> divided by x + 2
Oksanka [162]

The result of the division of polynomial <em>3.23 + 8x2 + 9x + 10</em> by <em>x + 2</em> is; 3x² + 2x +5

<h3>Long division of polynomials</h3>

According to the question given;

  • The result of the long division of polynomials can be evaluated as in the attached image.

By observation of the procedures in the attached image, we may conclude that the expressions (x+2) and (3x² + 2x +5) are factors of; 3x³ + 8x2 + 9x + 10

Learn more on polynomials division;

brainly.com/question/24662212

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2 years ago
9+3x=18-6x find for x
Sedbober [7]

Answer:

Hiya There!!!

_________________________

Isolate the variable by dividing each side by factors that don't contain the variable.

x =  1

_________________________

<em>“The harder you fall, the heavier your heart; the heavier your heart, the stronger you climb; the stronger you climb, the higher your pedestal.”</em><em> </em>

<em>― Criss Jami, Killosophy</em>

_________________________

<em>Think of life as a mytery because well it sort of is! You don't know what may happen may be good or bad but be a little curious and get ready for whatever comes your way!! </em><em>~Ashlynn </em>

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3 years ago
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