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3 years ago

I need the answer ASAP

Mathematics

1 answer:

gogolik [260]3 years ago

7 0

Answer:

Step-by-step explanation:

The shape cam be split into a triangle and a trapezoid

✔️Area of the trapezoid = ½(a + b)h

Where,

a = 12.5 ft

b = 16.7 ft

h = 11.6 ft

Plug in the values

Area of the trapezoid = ½(12.5 + 16.7)*11.6

Area of trapezoid = 169.36 ft²

✔️Area of the triangle = ½*b*h

b = 16.7 ft

h = 19.2 - 11.6 = 7.6 ft

Area of the triangle = ½*16.7*7.6

= 63.46 ft²

✔️Area of the shape = 169.36 + 63.46

= 232.82 ft²

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3 years ago

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Answer:

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Read 2 more answers

Simplify the expression.

Marizza181 [45]

$\bf \textit{Cofunction Identities}
\\ \quad \\
sin\left(\frac{\pi}{2}-{{ \theta}}\right)=cos({{ \theta}})\qquad 
\boxed{cos\left(\frac{\pi}{2}-{{ \theta}}\right)=sin({{ \theta}})}
\\ \quad \\ \quad \\
tan\left(\frac{\pi}{2}-{{ \theta}}\right)=cot({{ \theta}})\qquad 
cot\left(\frac{\pi}{2}-{{ \theta}}\right)=tan({{ \theta}})
\\ \quad \\ \quad \\
sec\left(\frac{\pi}{2}-{{ \theta}}\right)=csc({{ \theta}})\qquad 
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$\bf \\\\
-------------------------------\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta )
\\\\\\
\boxed{cos(\theta )=\sqrt{1-sin^2(\theta )}}$

$\bf \\\\
-------------------------------\\\\
\cfrac{cos^2\left(\frac{\pi }{2}-x \right)}{\sqrt{1-sin^2(x)}}\implies \cfrac{\left[ cos\left(\frac{\pi }{2}-x \right)\right]^2}{cos(x)}\implies \cfrac{[sin(x)]^2}{cos(x)}\implies \cfrac{sin(x)sin(x)}{cos(x)}
\\\\\\
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