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anyanavicka [17]
3 years ago
7

What is the sum of the 56 + 64 as the product of their GCF and another sum?

Mathematics
1 answer:
Tpy6a [65]3 years ago
7 0
My answer is 118 . because if you add them together you will make 118.
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Someone help please
drek231 [11]

Answer:

x = 30

Step-by-step explanation:

5 0
3 years ago
What is an equivalent expression for 1.5(3x + 4) + 0.25(6x + 8)?
eimsori [14]

Answer:

6x+8

Step-by-step explanation:

To answer this question we just simply use the distributive property to get rid of the parenthesis.

1.5*3x=4.5x

1.5*4=6

So the first parenthesis cancelled out would be : 4.5x+6

Now, onto the second:

0.25*6x=1.5x

0.25*8=2  

So the second one is : 1.5x+2

Not that we have distributed both things, we add these.

4.5x+6+1.5x+2 we combine like terms

4.5x+1.5x=6x

6+2=8

So, the answer is 6x+8

5 0
4 years ago
Read 2 more answers
16. Oceanside Bike
jenyasd209 [6]

Answer: he paid for 5 hours take

51.00-11.00 = 40.00 left

8/40= 5

so he paid for 5 hours

7 0
3 years ago
Read 2 more answers
The claim is that the standard deviation of the speeds of drivers in Bradford is 8 mph. An experienced driver feels that this is
Irina-Kira [14]

Answer:

Null hypothesis is rejected. Standard deviation is > 8 miles per hour

Step-by-step explanation:

σ [Population standard deviation] = 8 , s [sample standard deviation] = s

n [no of items] = 8

H0 [Null] : σ = 8 ; H1 [Alternate - Right Tail] : σ > 8

χ2 = (n - 1) . s^2 / σ^2

= 49 x (10.5)^2 / 82 = 5402.25 / 64

χ2 = 84.410

df [degree of freedom] = n -1 = 50 - 1 = 49

P value (χ^2 49 > 84.410) = 0.00125

p = 0.0013

p < α ie 0.05

So, H0 is rejected

Hence we state that standard deviation is > 8 miles per hpur

6 0
3 years ago
A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m. Based on past experience the company has determin
Gala2k [10]

Answer:

0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

P(c \leq X \leq d) = \frac{d - c}{b - a}

A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m.

We can consider 8 am = 0, and 8:30 am  = 30, so a = 0, b = 30

Find the probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.

Between 15 and 25, so:

P(15 \leq X \leq 25) = \frac{25 - 15}{30 - 0} = 0.3333

0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.

8 0
3 years ago
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