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2 years ago

Find the slope of the line that passes through two points (-6,2) (-4, -8).

Mathematics

1 answer:

Ksenya-84 [330]2 years ago

5 0

Answer:

the answer is $m=-5$

Step-by-step explanation:

Try using Symbolab, I use it all the time it gives the correct answer and it gives good explanations.

hope this helps :)

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What is the slope and y-intercept of the equation: y=1/5x-1

Alekssandra [29.7K]

Answer:

The slope is 1/5= rise/run

and y-intercepts is -1

Step-by-step

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3 years ago

Samantha rolls 2 dice at the same time. What is the probability that the

kykrilka [37]

Answer:

Step-by-step explanation:

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2 years ago

9x-23=49 what is the second step in this equation?

ladessa [460]

Answer:

Divide both sides by 9.

Step-by-step explanation:

To find the second step of the equation, we actually have to solve parts of the equation until we get to step 2.

Step 1: Add 23 to both sides.

$9x - 23 + 23 = 49 + 23$
$9x = 72$

Step 2: Divide both sides by 9.

$\frac{9x}{9} = \frac{72}{9}$
$x = 8$

Therefore, the second step is divide both sides by 9.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

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2 years ago

Answer this quick please

Ghella [55]

Answer:

$84s^{2} t\sqrt{35st}$

4 0

3 years ago

Read 2 more answers

Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1

algol [13]

Find the critical points of $f(x,y)$ :

$\dfrac{\partial f}{\partial x}=-2x=0\implies x=0$

$\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12$

All three points lie within $D$ , and $f$ takes on values of

$\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}$

Now check for extrema on the boundary of $D$ . Convert to polar coordinates:

$f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t$

Find the critical points of $g(t)$ :

$\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0$

$\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2$

$\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi$

where $n$ is any integer. There are some redundant critical points, so we'll just consider $0\le t< 2\pi$ , which gives

$t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3$

which gives values of

$\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}$

So altogether, $f(x,y)$ has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

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3 years ago