Assuming a normal distribution we find the standardized z scores for a:-
z1 = (80 - 180) / 25 = = -100/25 = -4
z2 = (280-180) / 25 = 4
Required P( -4 < z < 4) from the tables is >99.9%
b
z1 = 130-180 / 25 = -2
z2 = 230-180 / 25 = 2
from tables probability is 2* 0.4773 = 95.46 %
Answer:
Step-by-step explanation:
This would be called the range.
The cost of one shirt is 12.50 and cost of one pair of jeans is 24.75
Step-by-step explanation:
Let,
Cost of one shirt = x
Cost of pair of jeans = y
According to given statement;
4x+3y=124.25 Eqn 1
3x+5y=161.25 Eqn 2
Multiplying Eqn 1 by 3

Multiplying Eqn 2 by 4

Subtracting Eqn 3 from Eqn 4

Dividing both sides by 11

Putting 24.75 in Eqn 1

Dividing both sides by 4

The cost of one shirt is 12.50 and cost of one pair of jeans is 24.75
Keywords: linear equation, elimination method
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<h2>
The required "option D) 3.09" is correct.</h2>
Step-by-step explanation:
Given,
A portfolio has a E[r] = 12 %, and
A standard deviation (
) = 18 %
We know that,
Specify utility by U = E(r) – 0.5A
U = 0.12– 0.5(A) × 
= 0.12 - 0.5 × A × 0.0162
In order for the risky portfolio to be preferred to bills,
The following condition must have:
0.12 – 0.0162A > 0.07
⇒ A <
= 3.09
A must be less than 3.09 for the risky portfolio to be preferred to bills.
Thus, the required "option D) 3.09" is correct.
Use the above picture in helping you solve the problem!!
It is a positive and linear graph.