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Serjik [45]
2 years ago
11

Write the slope-intercept form of the equation of the line through the given point with the given slope. through: (1, 1), slope

= 2
Mathematics
1 answer:
RSB [31]2 years ago
7 0

Answer:

y=2x-1

Step-by-step explanation:

y-y1=m(x-x1)

y-1=2(x-1)

y=2x-2+1

y=2x-1

Please mark me as Brainliest if you're satisfied with the answer.

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Please help me with the answer ASAP
AleksandrR [38]

Answer:

g(x) is greater

Step-by-step explanation:

it is greater because when mulitplying the function g and x you get a higher number than you would with f(x)

hope that helps!!

5 0
2 years ago
Complete the unit rate:<br><br> 924 pages in 33 days : A.______ pages in B. _____ day/s
ValentinkaMS [17]

Answer:

28 pages in 1 day

Step-by-step explanation

you have to find the unit rate of pages to days, the number of days must be 1.

to find the amount of pages, you find 924/33, which equals 28.

a = 28

b = 1

8 0
3 years ago
Using the following figure, match the angles in the first column with their corresponding congruent angles in the second column.
Rus_ich [418]

Answer:

∠6 = ∠8

∠2 = ∠6

Step-by-step explanation:

Lines 'p' and 'q' are the parallel lines and line 'l' is a transversal line intersecting these lines at two distinct points.

By the property of alternate interior angles,

∠3 = ∠5

By the property of vertically opposite angles,

∠6 = ∠8

By the property of corresponding angles,

∠2 = ∠6

3 0
3 years ago
if a snowball rolls down a hill and its surface area increaces at a rate of 18cm^2/min, find the rate at which the radius increa
sp2606 [1]

Answer: dr/dt = 9/(24pi)  cm per minute

9/(24pi) is approximately equal to 0.119366

=============================================

Work Shown:

Given info

dS/dt = 18 cm^2/min is the rate of change of the surface area

r = 6 cm is the radius, from the fact that the diameter is 12 cm

--------

Use the surface area equation given, apply the derivative, plug in the given values and then isolate dr/dt which represents the rate of change for the radius

S = 4*pi*r^2

dS/dt = 2*4*pi*r*dr/dt

dS/dt = 8*pi*r*dr/dt

18 = 8*pi*6*dr/dt

18 = 48*pi*dr/dt

48pi*dr/dt = 18

dr/dt = 18/(48pi)

dr/dt = (9*2)/(24*2pi)

dr/dt = 9/(24pi)

The units are cm per minute, which can be written as cm/min.

3 0
3 years ago
What are the minimum, first quartile, median, third quartile, and maximum of the data set?
allochka39001 [22]
If we rearrange the given data set from lowest to highest, we have 
     3,\:6,\:7,\:8,\:10,\:12,\:15,\:18

The minimum is 3.

The first quartile is the average of 6 and 7, which is 6.5

The median is the average of 8 and 10 which is 9.

The third quartile is the average of 12 and 15 which is 13.5.

The maximum is 18. 
4 0
3 years ago
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