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Nataliya [291]
3 years ago
15

Dave determines the meal he ordered at the restaurant contains 14% of his daily sodium intake. If the meal contains 185 mg of so

dium, how many mg of sodium are in Dave's daily diet?
Mathematics
1 answer:
Triss [41]3 years ago
6 0

Answer:it is around 1321.42857

Step-by-step explanation:what i did was i divided 185 by 14 then multiplied what i got by 100

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given the midpoint of segment KL is M (1, -1) and L (8 ,-7) what are the coordinates of the other endpoint K
andrey2020 [161]

The answer is (-6, 5) for K.

In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.

(Kx + Lx)/2 = Mx

(Kx + 8)/2 = 1

Kx + 8 = 2

Kx = -6

And now we do the same thing for y values

(Ky + Ly)/2 = My

(Ky + -7)/2 = -1

Ky + -7 = -2

Ky = 5

This gives us the final point of (-6, 5)

7 0
3 years ago
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Which expression is equivalent to 2(3 - x) - 12 + 4x
iragen [17]
You would distribute then combine like terms to get your answer.

3 0
3 years ago
Is Circumference of a circle same as area?​
Klio2033 [76]

Answer:

The circumference of a circle is not the same as the area of the circle because the circumference represents the distance around the circle while the area represents the amount of space within the circle. Hope this helps.

5 0
3 years ago
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What is the length of AB?​
kozerog [31]

Answer: 6 units

Step-by-step explanation:

I know that in a triangle, there's two angles that have equal measures, then the sides opposite to them are equal in length. Thus, the length of side AB is 6 units.

8 0
2 years ago
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2. A square-based tent has the cross-sectional
ollegr [7]

(a) Length of the height is 2.732 m

(b) Length of the base is 5.466 m

<u>Explanation:</u>

An image is attached for reference.

(a)

In ΔAOB,

sin 30^o = \frac{AO}{AB} \\\\0.5 = \frac{AO}{2} \\\\AO = 1 m

In ΔBGD,

sin 60^o = \frac{BG}{BD} \\\\0.866 = \frac{BG}{2} \\\\BG = 1.732 m

According to the figure, BG = OE = 1.732 m

Height of the tent, AE = AO + OE

                                  = 1 m + 1.732 m

                                  = 2.732 m

(b)

DF = ?

In ΔAOB,

tan 30^o = \frac{AO}{OB} \\\\0.577 = \frac{1}{OB} \\\\OB = 1.733 m\\\\\\

According to the figure, OB = GE = 1.733 m

In ΔBGD,

tan 60^o = \frac{BG}{DG} \\\\1.732 = \frac{1.732}{DG}\\ \\DG = 1m

According to the figure, DE = DG + GE

                                      DE = 1 m + 1.733 m

                                     DE = 2.733 m

Length of the base, DF = 2 X DE

                              DF = 2 X 2.733 m

                               DF = 5.466 m

8 0
3 years ago
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