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the upper quartile is 160
PA is longer than the radius of the circle so Point A must be outside of the circle.
PB is less than the radius of the circle so Point B must be inside the circle.
Since the ray is going from A to B it is coming inside the circle and continuing in the other direction, therefore, it must exit the circle, giving us 2 contact points
Answer:
663.
Step-by-step explanation:
Answer:
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