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3 years ago

ASAP What is the multiplicity of the root (x^3-1)?

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

5 0

Answer: =(x - 1) x (x^2 + x + 1)

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Two containers designed to hold water are side by side, both in the shape of a

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Step-by-step explanation: v= $\pi$ r2h

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2 years ago

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Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]

Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

$f(x) = \frac{3x-2}{x+1}$
$g(x)=x+5$
f[ -4 ] = ?
g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

$f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}$

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

$g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13$

Therefore, the value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

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1 year ago

Germany has a population

egoroff_w [7]

Answer:

C. -186,205

Step-by-step explanation:

636,854 - 827,155 + 684,862 - 680,766

=> 1,321,716 - 1,507,921

=> -186,205

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2 years ago

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Makovka662 [10]

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