Please help me understand how to work out these types of equations?

Mathematics

2 answers:

Mademuasel [1]3 years ago

5 0

Answer:
115.2 other solutions is 576/5, 115 1/5
Step by step explanation:
To divide by a fraction, multiply by the reciprocal of the fraction
2.4 x (12 x 4)
Then multiply 12 and 4 which is 48
2.4 x 48
Then multiply 2.4 x 48
which is 115.2

goldenfox [79]3 years ago

5 0

Answer:

Step-by-step explanation:

2.4 (12 / 1/4)

First you do distributive property (multiplying the number in front of the parenthesis).

28.8 / 0.6

Then you just do the math

It's pretty easy, but it just depends on how somebody explains it.

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Three students share 5 peaches equally. How many peaches does each student get?

IceJOKER [234]

You can draw a picture and you can find your answer but the answer is 1 1/3 by the way

3 0

3 years ago

The table displays the number of students in each grade at Richmond High School who will or will not be attending the amusement

Pani-rosa [81]

Answer:

$P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$

Step-by-step explanation:

We are given a joint probability table.

There are four different graders in a school

1. Grade Ninth

2. Grade Tenth

3. Grade Eleventh

4. Grade Twelfth

Field trip refers to the students who will attending the amusement park field trip.

No field trip refers to the students who will not be attending the amusement park field trip.

We want to find out the probability that the selected student is an eleventh grader given that the student is going on a field trip.

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)}$

Where P(eleventh and FT) is the probability of students who are in eleventh grade and will be going to field trip

$P(eleventh\: and \: FT) = \frac{13}{92} \\\\P(eleventh \: and \: FT) = 0.1413$

Where P(FT) is the probability of students who will be going to field trip

$P(FT) = \frac{12}{92} + \frac{9}{92} + \frac{13}{92} + \frac{19}{92}\\\\P(FT) = 0.1304 + 0.0978 + 0.1413 + 0.2065\\\\P(FT) = 0.576 \\\\$

So the required probability is

$P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)} \\\\P( eleventh\: \: |\: \: FT)= \frac{0.1413}{0.576} \\\\P( eleventh\: \: |\: \: FT)= 0.2453 \\\\P( eleventh\: \: |\: \: FT)= 24.53\% \\\\$