Answer:
Step-by-step explanation:
Please help me understand how to work out these types of equations?
2 answers:
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Use the quadratic formula, x=
(don't know how to type the "-"sign in the formula, so there is only the "+" in the formula)
in this case, a=1, c=34, b is unknown
from the roots, we can tell that -b+
=2(5+3i)=10+6i
Note: the original equation already give b as -b, so -(-b)=10, b=10
using b^2-4ac=(6I)^2,
b^2-4*34=-36
b^2=100
you will also get b=10
(don't know how to type the "-"sign in the formula, so there is only the "+" in the formula)
in this case, a=1, c=34, b is unknown
from the roots, we can tell that -b+
Note: the original equation already give b as -b, so -(-b)=10, b=10
using b^2-4ac=(6I)^2,
b^2-4*34=-36
b^2=100
you will also get b=10
Answer:
Step-by-step explanation:
The solutions of a quadratic equation are :
x = -3/2 and x = 6
or we can write it as :
Multiplying both values,
Hence, the required quadratic equation is .