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Blizzard [7]
2 years ago
7

Under his cell phone plan, Elijah pays a flat cost of $64.50 per month and $5 per gigabyte. He wants to keep his bill at $87.50

per month. Write and solve an equation which can be used to determine g g, the number of gigabytes of data Elijah can use while staying within his budget.
Mathematics
1 answer:
timofeeve [1]2 years ago
8 0

Step-by-step explanation:

Plan A: A = 20G

Plan B: B = 15G + 40

To see when they will be equal set the equations equal to each other

20G = 15G + 40

5G = 40

G = 8

At 8 GB they will cost the same amount.

20(8) = $160

15(8)+40 = $160

Hope it will be Helpfull

thank you

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The type of activity that Jeff does at a speed of 4.5 miles per hour is Swimming

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem !

<em>This problem is about Kinematics.</em>

We will solve it in the following way

\texttt{Speed of Biking} = \texttt{Distance of Biking} \div \texttt{Time Taken}

\texttt{Speed of Biking} = \texttt{19} \div \texttt{2}

\texttt{Speed of Biking} = 9.5 \texttt{ miles per hour}

\texttt{ }

\texttt{Speed of Walking} = \texttt{Distance of Walking} \div \texttt{Time Taken}

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\texttt{Speed of Walking} = 3.5 \texttt{ miles per hour}

\texttt{ }

\texttt{Speed of Running} = \texttt{Distance of Running} \div \texttt{Time Taken}

\texttt{Speed of Running} = \texttt{15} \div \texttt{3}

\texttt{Speed of Running} = 5 \texttt{ miles per hour}

\texttt{ }

\texttt{Speed of Swimming} = \texttt{Distance of Swimming} \div \texttt{Time Taken}

\texttt{Speed of Swimming} = \texttt{18} \div \texttt{4}

\texttt{Speed of Swimming} = \boxed{4.5 \texttt{ miles per hour}}

\texttt{ }

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

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