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aev [14]
3 years ago
11

Ms. Wall will roll a single number cubes. What is the probability that she will roll an even number?

Mathematics
1 answer:
Arturiano [62]3 years ago
4 0
Well single number, meaning from 1 - 9. She has a higher chance of getting an odd number for sure, as there are more odd numbers on the dice :) So, the ratio is 4:5 and fraction: 4/5. %<span>44.444 is your answer :) 

Thank you,
Darian D.</span>
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The correct answer is 200 .
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The domain of a composite function (fog)(x) is the set of those inputs x in the domain of g for which g(x) is in the domain of f
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True, the correct answer is true.
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Katie has a collection of nickels, dimes and quarters with a total value of
garik1379 [7]

10d+ 25q+5n= 805

D= n+8

Q= n+ 5



10d+ 25q+5n= 805

10(n+8)+25(n+5)+5n=805

10n+80+25n+125+5n=805

40n+205=805

40n=805-205

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So 15 nickels ,23 dimes and 20quarters .


To check

15(0.05)= $0.75

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Add it

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5 0
3 years ago
How do you do long division how do you do long division on 35 / 2
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5 0
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Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p
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The question is an illustration of composite functions.

  • Functions c(n) and h(n) are \mathbf{c(n) = 5000 + 250n} and \mathbf{n(h) = 5h}
  • The composite function c(n(h)) is \mathbf{c(n(h)) = 5000 + 1250h}
  • The value of c(n(100)) is \mathbf{c(n(100)) = 130000}
  • The interpretation is: <em>"the cost of working for 100 hours is $130000"</em>

The given parameters are:

  • $5000 in fixed costs plus an additional $250
  • 5 systems in one hour of production

<u>(a) Functions c(n) and n(h)</u>

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

\mathbf{c(n) = Fixed + Additional \times n}

This gives

\mathbf{c(n) = 5000 + 250 \times n}

\mathbf{c(n) = 5000 + 250n}

The function for number of systems is:

\mathbf{n(h) = 5 \times h}

\mathbf{n(h) = 5h}

<u>(b) Function c(n(h))</u>

In (a), we have:

\mathbf{c(n) = 5000 + 250n}

\mathbf{n(h) = 5h}

Substitute n(h) for n in \mathbf{c(n) = 5000 + 250n}

\mathbf{c(n(h)) = 5000 + 250n(h)}

Substitute \mathbf{n(h) = 5h}

\mathbf{c(n(h)) = 5000 + 250 \times 5h}

\mathbf{c(n(h)) = 5000 + 1250h}

<u>(c) Find c(n(100))</u>

c(n(100)) means that h = 100.

So, we have:

\mathbf{c(n(100)) = 5000 + 1250 \times 100}

\mathbf{c(n(100)) = 5000 + 125000}

\mathbf{c(n(100)) = 130000}

<u>(d) Interpret (c)</u>

In (c), we have: \mathbf{c(n(100)) = 130000}

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

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3 years ago
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