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4 years ago

HELP!!!!! does anyone know !!!

Mathematics

1 answer:

Ray Of Light [21]4 years ago

7 0

Answer:

39,47,55,65,75.

Step-by-step explanation:

Plug in : 35+0.4m

35+0.4(10)m

35+4m

39m

just plug in and write 39,47,55,65,75.

Hope this helps plz hit the crown :D

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Brenda's school is selling tickets to a spring musical. On the first day of ticket sales the school sold 3 senior citizen ticket

Feliz [49]

We can form two equations, let the price of a senior ticket be s and the price of a child ticket be c.
We have from day 1:
A: 3s + 9c = 75
And from day 2:
B: 8s + 5c = 67

Now we can rewrite A as:
A: 24s + 72c = 600
And can rewrite B as:
B: 24s + 15c = 201

Now A-B can be written as:
A-B: 57c = 399

So c = 7

Now substituting this back into A we get:
A: 3s + 63 = 75
A: 3s = 12

So s = 4

We have the price of a senior ticket is $4 and the price of a child ticket is $7

3 0

3 years ago

What is a possible number greater than or equal to 7?

BARSIC [14]

Answer:

8,7,11,7.5,10000 any number that is 7, or bigger!

Step-by-step explanation:

7 0

3 years ago

What is the correct equilibrium constant expression for this equation? 2 upper C upper o upper F subscript 2 (g) double arrow up

Alekssandra [29.7K]

The correct equilibrium constant expression for this equation is;

$\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}$

Given

Consider the equation below.

$\rm {2COF_2(g)}\rightleftharpoons C0_2(g)+CF_4(g)$

<h3>What are Species?</h3>

In an equilibrium constant expression, you do not include the solid substances; only gases and dissolved substances.

<h3>Equilibrium constant expression;</h3>

It is the quotient of the product of the concentrations of the species on the right-hand side of the equilibrium equation, each raised to its corresponding coefficient, and the product of the concentrations of the species on the left-hand side, each raised to its corresponding coefficient.

Therefore,

The correct equilibrium constant expression for this equation is;

$\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}$

Hence, the correct equilibrium constant expression for this equation is;

$\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}$ .

To know more about Equilibrium constant click the link is given below.

brainly.com/question/19240570

3 0

2 years ago

I only need help with the last one the circle one to be pacific. I need help by tonight so I can get this done.

Degger [83]

Answer:

$V = 997.8 {cm}^{3}$

Step-by-step explanation:

The last one is spherical

The volume of a sphere is given by:

$V= \frac{4}{3} \pi \: {r}^{3}$

From the diagram, the the radius is r=6.2 cm.

We substitute to get:

$V= \frac{4}{3} \times 3.14\: \times {6.2}^{3}$

This evaluate to;

$V = 997.8 {cm}^{3}$

6 0

3 years ago

The service life of a battery used in a cardiac pacemaker is assumed to be normally distributed. A random sample of ten batterie

Fittoniya [83]

Answer:

The confidence interval is $25.16 < \mu < 26.85$

Step-by-step explanation:

From the question we are given a data set

25.5, 26.1, 26.8, 23.2, 24.2, 28.4, 25.0, 27.8, 27.3, and 25.7.

The mean of the this sample data is

$\= x = \frac{\sum x_i}{n}$

where is the sample size with values n = 10

$\= x = \frac{25.5+ 26.1+ 26.8+23.2+ 24.2+ 28.4+ 25.0+ 27.8+ 27.3+ 25.7}{10}$

$\= x = 26$

The standard deviation is evaluated as

$\sigma = \sqrt{\frac{\sum (x-\= x)}{n} }$

substituting values

$= \sqrt{\frac{ ( 25.5-26)^2, (26.1-26)^2, (26.8-26)^2, (23.2-26)^2}{10} }$

$\cdot \ \cdot \ \cdot \sqrt{\frac{ ( 24.2-26)^2, (28.4-26)^2+( 25.0-26)^2+ (27.8-26)^2+( 27.3-26)^2+( 25.7-26)^2}{10} }$

$\sigma = 1.625$

The confidence level is given as 90% hence the level of significance is calculated as

$\alpha = 100 -90$

$\alpha =10$ %

$\alpha = 0.10$

Now the critical values of $\frac{\alpha }{2}$ is obtained from the normal distribution table as

$Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining the critical values of $\frac{\alpha }{2}$ instead of $\alpha$ is because we are considering two tails of the area under the normal curve