A solution of a quadratic equation (ax^2+bx+c) is the point at which the parabola crosses the x-axis. We can find this by using the Quadratic formula, which is
. We can solve the equation as follows:
Then we separate the negative from -28 to get:
Then we continue to solve by factoring common terms (-2 and 2). We get the solutions of
. Choice
B matches our first solution.
:)
Answer:
j
Step-by-step explanation:
egfebhbhbdhfbhdfdbbdhbdb b ecbhhbebfqen fqe ffb
We find<span> the first derivative of the curve, and evaluate it at </span>x<span>=1 (which we will use to obtain the </span>slope<span> of the </span>line tangent<span> to the curve at (1,−1)). So we have a </span>point<span> on the </span>tangent line: (x0,y0<span>)=(1,−1) and the </span>slope<span> of the </span>line tangent<span> at that </span>point<span>: m=−13.</span>
You could put 70/100 and cross multiple with x/5,000 first multiple 5,000 by 70 then divide by 100 meaning x=3,500
Answer:
a or b
Step-by-step explanation:
i not so sure