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Brums [2.3K]
2 years ago
14

I need help on this i need help on this​

Mathematics
1 answer:
elena55 [62]2 years ago
3 0

Answer:

A

Step-by-step explanation:

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Bumek [7]

Answer:

7/12

Step-by-step explanation:

3 0
2 years ago
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Give the equation of the circle centered at the origin and passing through the point (0,-8)
Norma-Jean [14]

Answer:

The answer to your question is x ² + y² = 64

Step-by-step explanation:

Process

1.- Find the length of the radius

C (0, 0)

P (0, -8)

d = \sqrt{(x2 - x1)^{2}+ (y2 - y1)^{2}  }

d = \sqrt{(0- 0)^{2}+ (-8 - 0)^{2}  }

d = \sqrt{64}

d = 8

2.- Find the equation of the circle

    (x - h)^{2} + (y - k)^{2} = r^{2} \\

h = 0   and k = 0

    (x - 0)^{2} + (y - 0)^{2} = 8^{2}

            x² + y² = 64      

5 0
3 years ago
An astronaut on the moon throws a baseball upward. The astronaut is 6 ft 6 in tall, and the initial velocity of the ball is 40 f
weqwewe [10]

Answer:

t = 0.293 s and 14.52 s

Step-by-step explanation:

The heights of the ball in feet is given by the equation as follows :

S = -2.7t^2+40t+6.5

Where t is the number of seconds after the ball was thrown.

We need to find is the ball 18 ft above the moon's surface.

Put S = 18 ft

-2.7t^2+40t+6.5=18\\\\-2.7t^2+40t=18-6.5\\\\-2.7t^2+40t-11.5=0

It is a quadratic equation. Its solution is given by :

t=\dfrac{-40+\sqrt{40^{2\ }-4\left(-2.7\right)\left(-11.5\right)}}{2\left(-2.7\right)},\dfrac{-40-\sqrt{40^{2\ }-4\left(-2.7\right)\left(-11.5\right)}}{2\left(-2.7\right)}\\\\t=0.293\ s,14.52\ s

So, the ball is at first 0.293 s and then 14.52 s above the Moon's surface.

8 0
3 years ago
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olchik [2.2K]
1)Not a function

2)yes

3)not a function
8 0
3 years ago
The graph of y=-3x + 2 is:
UkoKoshka [18]

Answer:

the graph of y^2+3x=0 is symmetric with respect to which axis

Step-by-step explanation:

3 0
3 years ago
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