Given :Enzo wins 5 tickets from every game, and Beatriz wins 11 tickets from every game.We need to find the minimum number of games that Enzo could have played to win the same number of tickets.
The minimum number of games that Enzo could have played to win the same number of tickets Will be the least common multiple of 11 and 5.
The factors of 11 and 5 are
11=11x1
5= 5x1
Least common multiply = 11x5=5.
The minimum number of games that Enzo could have played to win the same number of tickets is 55.
9/16 is 36/64 in simplest form hope i helped
The answer is: 2(x−6)(x+2)<span>
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Answer:
2.09 seconds.
Step-by-step explanation:
We are given...
y = 70 feet
v0 = 0 feet/second
a = 32 feet/second^2
We need to find t using the following equation...
y = v0 * t + (1/2) * a * t^2
70 = 0 * t + (1/2) * 32 * t^2
70 = (1/2) * 32 * t^2
70 = 16t^2
16t^2 = 70
t^2 = 4.375
t = sqrt(4.375)
t = 2.091650066
So, it will take the toy about 2.09 seconds to hit the ground.
Hope this helps!
Answer:
my answer would be b
Step-by-step explanation:
i ithink its be because it makes the most sense
