3 years ago

Whats the radius of a circle whose equation is x^2+y^2=16

Mathematics

2 answers:

kvv77 [185]3 years ago

8 0

Answer:

Step-by-step explanation:

We can write the equation of a circle as

(x-h)^2 + (y-k)^2 = r^2

where (h,k) is the center and r is the radius

x^2 + y^2 = 16

can be rewritten as

(x-0)^2 + (y-0)^2 = 4^2

Where the center is (0,0) and the radius is 4

Zina [86]3 years ago

4 0

Answe

Step-by-step explanation:

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3 years ago

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Gennadij [26K]

Answer:

<h2>The Mean Absolute Vale (MAD) is 4.4</h2>

Step-by-step explanation:

The mean absolute deviation is defined as

$MAD=\frac{\sum |x_{i}-\mu |}{N}$

Where $\mu$ is the mean and $N$ is the total number of data.

The means is defined as

$\mu = \frac{\sum x_{i} }{N}=\frac{25+28+20+22+32+28+35+34+30+36}{10}=\frac{290}{10}=29$

And, $N=10$

Replacing these values, in the MAD formula, we have

$MAD=\frac{|25-29|+|28-29|+|20-29|+|22-29|+|32-29|+|28-29|+|35-29|+|34-29|+|30-29|+|36-29|}{10} \\MAD=\frac{|-4|+|-1|+|-9|+|-7|+|3|+|-1|+|6|+|5|+|1|+|7|}{10}=\frac{44}{10}\\ MAD = 4.4$

Therefore, the Mean Absolute Vale (MAD) is 4.4

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