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aliya0001 [1]
3 years ago
8

Zoe‘s graduation picnic cost $94 for the decorations plus an additional $10 for each attendee at Moose how many attendees can th

ere be if Zoe budgets a total of $474 for her graduation picnic
Mathematics
1 answer:
densk [106]3 years ago
6 0

Answer:

38 attendees.

Step-by-step explanation:

Subtract the cost of the decorations from the total (474 - 94). You are then left with $380 for all the attendees combined. Divide the total cost of attendees by the cost per attendee (380/ 10). You are left with 38 attendees. You can also check this backwards by multiplying 38 attendees by $10 (380), then adding the cost of decorations (94), and end up with the total cost of $474. I hope this helped!

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Answer: x=−9/4

Step-by-step explanation:

Let's solve your equation step-by-step.

−2(x+14)+1=5

Step 1: Simplify both sides of the equation.

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7 0
3 years ago
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Find the surface area of the cylinder in terms of Tt
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2 years ago
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The odds in favor of a horse winning a race are 7:4. Find the probability that the horse will win the race.
Sliva [168]

Answer:

7/11 = 0.6363...

Step-by-step explanation:

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3 years ago
To test if the mean IQ of employees in an organization is greater than 100, a sample of 30 employees is taken and the value of t
ivolga24 [154]

Answer:

p_v =P(t_{(29)}>1.42)=0.0831  

For this case the p value calculated is higher than the significance level used of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

a) do not reject the null hypothesis and conclude that the mean IQ is not greater than 100

Step-by-step explanation:

Information given

We want to verify if he mean IQ of employees in an organization is greater than 100 , the system of hypothesis would be:  

Null hypothesis:\mu \leq 100  

Alternative hypothesis:\mu > 100  

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

The statistic calculated for this case  t_{calc}= 1.42

The degrees of freedom are given by:

df=n-1=30-1=29  

Now we can find the p value using tha laternative hypothesis and we got:

p_v =P(t_{(29)}>1.42)=0.0831  

For this case the p value calculated is higher than the significance level used of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

a) do not reject the null hypothesis and conclude that the mean IQ is not greater than 100

5 0
3 years ago
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