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2 years ago

One book costs £2.99 how much do six books cost

Mathematics

2 answers:

Advocard [28]2 years ago

7 0

£13.98 I think !!!!!

Evgen [1.6K]2 years ago

4 0

One book costs £2.99 6 books cost £18.00

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Estimate 856 + 457 by first rounding each number to the nearest hundred.

Lisa [10]

Answer:

865 = 900

457 = 500

900 + 500 = 1,400

856 + 457 = 1,313

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2 years ago

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Find x- and y-intercepts. Write ordered pairs representing the points where the line crosses the axes. Note x-intercept is a poi

GenaCL600 [577]

Your answer would be -2/3 and that is in slope y-intercept is (0,2)

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3 years ago

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Kenny is 8 years older than Andrew. Tim is 3 times

9966 [12]

Answer:

Kenny is 18 years old Andrew is 10 years old Tim is 30 years old and Cameron is 5 years old

Step-by-step explanation:

Let a be Kenny's age , b be Andrew's age , c be Tim's age , d be Cameron's age

( b < a , b<c , d<b)

Kenny is 8 years older than Andrewn = > a = b + 8 (1)

Tim is 3 times as old as Andrew => c = 3 . b (2)

Cameron is 5 years younger than Andrew => d = b-5 (3)

The combined age of the four is 63 => a+b+c+d = 63 (4)

(1),(2),(3),(4) => b+8 + b + 3b + b-5 = 63 <=> 6b + 3 = 63 <=> b = 10

=> a= 10+8 =18, c = 3 . 10 = 30, d= 5

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3 years ago

Which table represents the same linear relationship as y =2x + 6.

Vika [28.1K]

Answer:

I think the last one

Step-by-step explanation:

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2 years ago

Given T5 = 96 and T8 = 768 of a geometric progression. Find the first term,a and the common ratio,r.

Alona [7]

Answer:

Of the given geometric sequence, the first term a is 6 and its common ratio r is 2.

Step-by-step explanation:

Recall that the direct formula of a geometric sequence is given by:

$\displaystyle T_ n = ar^{n-1}$

Where Tₙ is the nth term, a is the initial term, and r is the common ratio.

We are given that the fifth term T₅ = 96 and the eighth term T₈ = 768. In other words:

$\displaystyle T_5 = a r^{(5) - 1} \text{ and } T_8 = ar^{(8)-1}$

Substitute and simplify:

$\displaystyle 96 = ar^4 \text{ and } 768 = ar^7$

We can rewrite the second equation as:

$\displaystyle 768 = (ar^4) \cdot r^3$

Substitute:

$\displaystyle 768 = (96) r^3$

Hence:

$\displaystyle r = \sqrt[3]{\frac{768}{96}} = \sqrt[3]{8} = 2$

So, the common ratio r is two.

Using the first equation, we can solve for the initial term:

$\displaystyle \begin{aligned} 96 &= ar^4 \\ ar^4 &= 96 \\ a(2)^4 &= 96 \\ 16a &= 96 \\ a &= 6 \end{aligned}$

In conclusion, of the given geometric sequence, the first term a is 6 and its common ratio r is 2.

7 0

2 years ago