Question

In a circle with center P and radius 10cm. If one of the chord is of length 12 cm.

Answer 1

Answer:

The distance of the chord from the center is 8cm

Step-by-step explanation:

$\sf{}$

•Length of chord=12cm

•Half of the cord=12/2=6cm

•Radius=10cm

By using Pythagorean theorem:

P= √H²-√B²

P= √10²-√6²

P=√100-√36

P=√64

P= 8cm

Answer 2

Look at the attachment

The line bisects the cord which we have to find

• Length of chord=12cm
• Half of the cord=12/2=6cm
• Radius=10cm

Its a right angle triangle

• using Pythagorean theorem

$\boxed{\sf P^2=H^2-B^2}$

$\\ \Large\sf\longmapsto P=\sqrt{H^2-B^2}$

$\\ \Large\sf\longmapsto P=\sqrt{10^2-6^2}$

$\\ \Large\sf\longmapsto P=\sqrt{100-36}$

$\\ \Large\sf\longmapsto P=\sqrt{64}$

$\\ \Large\sf\longmapsto P=8cm$

Distance of the chord from centre is 8cm.