You can write every speed as the ratio between the space and time, so in this case you have
One group (A) contains 390 people. Three-fifths of the people in group A will be selected to win $100 fuel cards. There is anoth
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When graphing, its how much you rise and run
thats the formula when u have a graph and the question is asking for the slope.
you chose a point, and go down or up however many times it goes to the next point, and you run to the left however many times it gets you to get to that point.
if the line goes downward the slope is therefore negative, and if the line goes upward, the slope is therefore, positive.
m in math is meant to be slope, so
thats the formula when u have a graph and the question is asking for the slope.
you chose a point, and go down or up however many times it goes to the next point, and you run to the left however many times it gets you to get to that point.
if the line goes downward the slope is therefore negative, and if the line goes upward, the slope is therefore, positive.
m in math is meant to be slope, so
<u><em>Answer:</em></u>
Option b
<u><em>Explanation:</em></u>
The question is shown in the attached image
To answer this question, we will simply substitute in the given expressions with the values y=2 and y=5
The correct option will be the one having equal vales in both cases
<u>1. Option a:</u>
<u>At y = 2:</u>
2y - 1 = 2(2) - 1 = 3
3y - 5 + y = 3(2) - 5 + 2 = 3
<u>At y = 5:</u>
2y - 1 = 2(5) - 1 = 10
3y - 5 + y = 3(5) - 5 + 5 = 15
This option is <u>incorrect</u>, since both expressions are not equal at y = 5
<u>2. Option b:</u>
<u>At y = 2:</u>
5y + 4 = 5(2) + 4 = 14
7y + 4 - 2y = 7(2) + 4 - 2(2) = 14
<u>At y = 5:</u>
5y + 4 = 5(5) + 4 = 29
7y + 4 - 2y = 7(5) + 4 - 2(5) = 29
This option is <u>correct</u>, since both expressions are equal at the two vales of y
<u>3. Option c:</u>
<u>At y = 2:</u>
y + 7 = 2 + 7 = 9
y + 2 + y = 2 + 2 + 2 = 6
<u>At y = 5:</u>
y + 7 = 5 + 7 = 12
y + 2 + y = 5 + 2 + 2 = 12
This option is <u>incorrect</u>, since both expressions are not equal at y = 2
<u>4. Option d:</u>
<u>At y = 2:</u>
3y - 4 = 3(2) - 4 = 2
3y - 2 + y = 3(2) - 2 + 2 = 6
<u>At y = 5:</u>
3y - 4 = 3(5) - 4 = 11
3y - 2 + y = 3(5) - 2 + 5 = 18
This option is <u>incorrect</u>, since both expressions are neither equal at y = 2 or y = 5
Hope this helps :)
