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enyata [817]
3 years ago
6

The set of odd numbers greater than 7 infinite or finite?

Mathematics
1 answer:
mars1129 [50]3 years ago
4 0
There are infinite odd numbers greater than 7

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The width of a rectangle is (5x + 2) inches and the length is (6x − 7) inches. Find the area of the rectangle.
Degger [83]

Answer:

<h2><u><em>30x² − 23x − 14</em></u></h2>

Explanation:

  • Area = Length · Width

Length: (6x - 7)

Width: (5x + 2)

  • Create An Equation

(6x - 7) (5x + 2)

= (6x + −7)(5x + 2)

(6x)(5x) + (6x)(2) + (−7)(5x) + (−7)(2)

= 30x² + 12x − 35x − 14

  • 30x² − 23x − 14

- PNW

7 0
2 years ago
Bill has enough money to buy no more than 1/2 pound of cheese. how much cheese could he buy?
quester [9]
Let
 x: amount of pounds of cheese that Bill can buy.
 We can write the following inequation for this problem
 x <= 1/2
 Therefore, Bill could buy up to 1/2 pound of cheese.
 answer
 1/2 pound of cheese (maximum)
7 0
3 years ago
A rectangle has a a perimeter of 72 ft. The length and width are scaled by a factor 3.5.
jarptica [38.1K]
Formula for perimeter of rectangle:
P=2(L+w)
P=2L+2w
Here Perimeter, p= 72 ft
And scale factor of length and width=3.5 which means rectangle is enlarged.
So perimeter of rectangle= 3.5 x 72
P=252ft 

Answer: 252 ft

8 0
3 years ago
Read 2 more answers
I need help with this question​
Artyom0805 [142]

Answer:

Step-by-step explanation:

It's algebra really, basically make a system of equations.

1b+5j=t

3b+2j=2t

I'm gonna solve the first one for buckets so we have it in terms of jars.

b+5j=t

b=t-5j

Now I plug that into the other equation

3b+2j=2t

3(t-5j)+2j=2t

3t-15j+2j=2t

Now, since it wants how many jars are in one tub, I want to solve it so there's 1t on one side of the equation and all js on the other.  or it other words solve for t.

3t-15j+2j=2t

3t-13j = 2t

3t = 2t+13j

t = 13j

So it takes 13 jars to make one tub, or one jar is 1/13 of a tub.  You could then plug that in to one of the equations and find how much a  bucket is.  

5 0
3 years ago
Determine the area of the square ABCD with AB=3cm<br>​
Svetach [21]

Side=3cm

\\ \tt\longmapsto Area=(side)^2

\\ \tt\longmapsto Area=3^2

\\ \tt\longmapsto Area=9cm^2

5 0
2 years ago
Read 2 more answers
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