What is the area of right triangle ABC where the dimensions of the two legs
1 answer:
Answer:
3x^2+17/2x-7
Step-by-step explanation:
area = 1/2 base * height
1/2 (2x+7) (3x-2) you must distribute first.
6x^2-4x+21x-14
3x^2 +17/2x-7
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