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allochka39001 [22]

3 years ago

7

Which of the following is the value of a when the function f(x)=3|xl is written in the standard form of an absolute value

1 answer:

Monica [59]3 years ago

7 0

F(x)=|x| is the simplified version of an absolute function such as the parent function

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What is i^15 for imaginary numbers

allochka39001 [22]

Answer:

1^15 is 15

Step-by-step explanation:

7 0

3 years ago

Help!!!! And is the first on correct

ExtremeBDS [4]

2s+5<span>≥49

First: Subtract 5 on both sides
You'll get: 2s </span><span>≥ 44
Last: Divide each side by 2 so your s would be alone
You'll get: s </span><span>≥ 22 <That would be your answer

HOPE THIS HELPS! ^_^</span>

7 0

3 years ago

Find the area of polygon PQRS.

Molodets [167]

Answer:

12 unit squared....................

7 0

3 years ago

Find the distance of the point (3,4) from the midpoint of the line joining (8,10) and (4,6)

Elis [28]

Answer:

Distance between point $(3,4)$ and midpoint of line joining $(8,10)$ and $(4,6)$ = $5$ units.

Step-by-step explanation:

Given:

Points:

$A(3,4)\\B(8,10)\\C(4,6)$

To find distance from point A to midpoint of BC.

Midpoint M of BC:

$M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\$

$M=(\frac{8+4}{2},\frac{10+6}{2})\\$ [Plugging in points $B(8,10)\ and\ C(4,6)$ ]

$M=(\frac{12}{2},\frac{16}{2})\\$

$M=(6,8)\\$

Distance between A and M:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\$

$D=\sqrt{(6-3)^2+(8-4)^2} \\$ [Plugging in points $A(3,4)\ and\ M(6,8)$ ]

$D=\sqrt{(3)^2+(4)^2} \\$

$D=\sqrt{9+16} \\$

$D=\sqrt{25} \\$

$D=\pm5$

Since distance is always positive ∴ $D= 5$ units

4 0

3 years ago

What are the input and output value for determining the sine of 60?

inna [77]

<h2>Explanation:</h2><h2 />

The input of a function is also called the domain and are those x-values for which the function is defined.

The output of a function is also called the range and are those y-values for which the function is defined.

Here we have the following function:

$y=f(x)=sin(x)$

And we know that:

Input:

$\boxed{x=60^{\circ}}$

Output:

$y=sin(60^{\circ}) \\ \\ \therefore \boxed{y=\frac{\sqrt{3}}{{2}}}$

7 0

3 years ago

Read 2 more answers