the answer for find the lcm of 8,12 and 16 is answer a.48
Answer: 22 hours 11 minutes
<u>Step-by-step explanation:</u>
![22\ hours + \bigg[\dfrac{19}{100}=\dfrac{x}{60}\bigg]\\\\22\ hours + 11\ minutes](https://tex.z-dn.net/?f=22%5C%20hours%20%2B%20%5Cbigg%5B%5Cdfrac%7B19%7D%7B100%7D%3D%5Cdfrac%7Bx%7D%7B60%7D%5Cbigg%5D%5C%5C%5C%5C22%5C%20hours%20%2B%2011%5C%20minutes)
Answer:
Assuming that all three sides are 9 inches then the answer should 729.
Step-by-step explanation:
Just multiply 9*9*9. The formula to get volume is (length)*(width)*(height).
Step One
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Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
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Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
Answer:
y + 3 = -1(x-1)
Step-by-step explanation:
sub (1, -3) and slope = -1:
y - (-3) = -1(x - 1)
Topic: Coordinate Geometry
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