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3 years ago

What is the exponential regression equation for the data set?

Mathematics

2 answers:

inna [77]3 years ago

8 0

The answer is B. Y^=0.33・1.11x
Hope this helps. I just took the test and it was the correct answer for me.

Tpy6a [65]3 years ago

7 0

Answer:

yˆ=0.33·1.11x

Step-by-step explanation:

This equation correctly represents the data table.

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Helppppppppppppppp !!!!!!

algol [13]

Answer:

$\sqrt{2^{5} }$ is correct

Step-by-step explanation:

6 0

3 years ago

Which of the following is ordered from least to greatest?

zubka84 [21]

The fourth one should be the correct answer

5 0

4 years ago

Read 2 more answers

Factor 8x^3y + 38x^2y - 10xy

Sophie [7]

Answer:

2xy(x+5)(4x−1)

Step-by-step explanation:

1 Find the Greatest Common Factor (GCF).

GCF = 2xy

2 Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

2xy (8x^3y + 38x^2y/2xy + −10xy/2xy)

3 Simplify each term in parentheses.

2xy(4x^2 +19x−5)

4 Split the second term in 4x^2+19x-5 into two terms.

2xy(4x^2 +20x−x−5)

5 Factor out common terms in the first two terms, then in the last two terms.

2xy(4x(x+5)−(x+5))

6 Factor out the common term x+5.

2xy(x+5)(4x−1)

7 0

2 years ago

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection = </em>

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago

Help! Brainly to the first person!

barxatty [35]

It’s 60! i had that and got it correct. hope this helps :)

8 0

3 years ago